\
rHt@H|@=HtDH|BJdLJTH:ITEI\\E=ILPILNNtCNlB:8N4t"W t"4u"
p"4zI[ Il@=HlHH|HIDLILIJDII|HKDAJ|A:JtCJtC=JdLJtJL\
THLdFNk|Nc|\
:8K"; main (
int C,char** A) {for(x=A[1],i=calloc(strlen(x)+2,163840);
C-1;C<3 Q=_= 0,(z[1]=*x++) ((*x++==104 z[1]^=32:--x), X =
strstr(Z,z)) &&(X+=C++):(printf("P2 %d 320 4 ",V=b/2+32),
V*=2,s=Q=0,C =4):C<4 Q-->0 i[(int)((l+=o)+b)][(int)(k+=B)
]=1:_ _-=.5/ 256,o=(v(2)-(l=v(0)))/(Q=16),B=(v(3)-(k=v(1)
))/Q:*X>60 y ,q(L[4],L[5])q(L[6],L[7])*X-61||(++X,y,y,y),
Y:*X>57 ++X, y,Y:*X >54 ++X,b+=*X++%64*4:--C:printf("%d "
,i[Q][s]+i[Q ][s+1]+i[Q+1][s]+i[Q+1][s+1])&&(Q+=2)
0,s+=2)<640
||(C=1));}
编译后在dos下输入abs > ioccc_ray.ppm,生成一个图片(等得可能有点久)
程序代码
X=1024; Y=768; A=3;
J=0;K=-10;L=-7;M=1296;N=36;O=255;P=9;_=1<<15;E;S;C;D;F(b){E="1""111886:6: AAF"
"FHHMMOO55557799@@>>>BBBGGIIKK"[b]-64;C="C@=::C@@==@=:C@=:C@=:C5""31/513/5131/"
"31/531/53"[b ]-64;S=b<22 9:0;D=2;}I(x,Y,X){Y (X^=Y,X*X>x (X^=Y):0, I (x,Y/2,X
)):(E=X); }H(x){I(x, _,0);}p;q( c,x,y,z,k,l,m,a, b){F(c
);x-=E*M ;y-=S*M ;z-=C*M ;b=x* x/M+ y*y/M+z
*z/M-D*D *M;a=-x *k/M -y*l/M-z *m/M; p=((b=a*a/M-
b)>=0 (I (b*M,_ ,0),b =E, a+(a>b -b:b)): -1.0);}Z;W;o
(c,x,y, z,k,l, m,a){Z=! c -1:Z;c <44 (q(c,x ,y,z,k,
l,m,0,0 ),(p> 0&&c!= a&& (p
p,Z=c): 0,o(c+ 1, x,y,z, k,l, m,a)):0 ;}Q;T;
U;u;v;w ;n(e,f,g, h,i,j,d,a, b,V){o(0 ,e,f,g,h,i,j,a);d>0
&&Z>=0 (e+=h*W/M,f+=i*W/M,g+=j*W/M,F(Z),u=e-E*M,v=f-S*M,w=g-C*M,b=(-2*u-2*v+w)
/3,H(u*u+v*v+w*w),b/=D,b*=b,b*=200,b/=(M*M),V=Z,E!=0 (u=-u*M/E,v=-v*M/E,w=-w*M/
E):0,E=(h*u+i*v+j*w)/M,h-=u*E/(M/2),i-=v*E/(M/2),j-=w*E/(M/2),n(e,f,g,h,i,j,d-1
,Z,0,0),Q/=2,T/=2, U/=2,V=V<22 7: (V<30 1:(V<38 2:(V<44 4:(V==44 6:3))))
,Q+=V&1 b:0,T +=V&2 b :0,U+=V &4 b:0) :(d==P (g+=2
,j=g>0 g/8:g/ 20):0,j >0 (U= j *j/M,Q =255- 250*U/M,T=255
-150*U/M,U=255 -100 *U/M):(U =j*j /M,U
/M,T=255-435*U /M,U=255 -720* U/M):(U -=M/5,Q=213-110*U
/M,T=168-113*U / M,U=111 -85*U/M) ),d!=P (Q/=2,T/=2
,U/=2):0);Q=Q< 0 0: Q>O O: Q;T=T<0 0:T>O O:T;U=U<0 0:
U>O O:U;}R;G;B ;t(x,y ,a, b){n(M*J+M *40*(A*x +a)/X/A-M*20,M*K,M
*L-M*30*(A*y+b)/Y/A+M*15,0,M,0,P, -1,0,0);R+=Q ;G+=T;B +=U;++a
b):(++b
/A/A,B/A/A),r(x+1,y)):0;}s(y){r(0,--y s(y),y:y);}main(){printf("P6\n%i %i\n255"
"\n",X,Y);s(Y);}
编译后输入abc 0 0 1可以画出x^2的函数图像,输入abc -1 0 0 1可以画出x^3-1的图像。你也可以试试其它的。
程序代码
#include
#include
#include
#define _ ;double
#define void x,x
#define case(break,default) break[O]:default[O]:
#define switch(bool) ;for(;x
#define do(if,else) inIine(else)>int##if
#define true (--void++)
#define false (++void--)
char*O=" <60>! \\\n"_ doubIe[010]_ int0,int1 _ Iong=0 _ inIine(int eIse){int
O1O=!O _ l=!O;for(;O1O<010;++O1O)l+=(O1O[doubIe]*pow(eIse,O1O));return l;}int
main(int booI,char*eIse[]){int I=1,x=-*O;if(eIse){for(;I<010+1;I++)I[doubIe-1]
=booI>I atof(I[eIse]):!O switch(*O)x++)abs(inIine(x))>Iong&&(Iong=abs(inIine(x
)));int1=Iong;main(-*O>>1,0);}else{if(booI<*O>>1){int0=int1;int1=int0-2*Iong/0
[O]switch(5[O]))putchar(x-*O (int0>=inIine(x)&&do(1,x)do(0,true)do(0,false)
case(2,1)do(1,true)do(0,false)6[