if (text[i] == '[') {
left = i;
} else if (text[i] == ']') {
right = i;
break;
}
}
count = right - left - 1;
if (count <= 0) { // 没有正则匹配
for (i = j = 0; i < len; i ++) {
if (text[i] != '[' && text[i] != ']') {
newtext[j ++] = text[i];
}
}
newtext[j] = '\0';
for (i = 0; i < n; i ++) {
if (strcasecmp(strs[i].name, newtext) == 0) {
printf("%d %s\n", i + 1, strs[i].name);
}
}
}else { // 需要正则匹配
for (j = 1, k = 0; j <= count; j ++, k ++) { // 构建文本数组
memset(t[k].name, '\0', sizeof(t[k].name));
for (i = 0; i < left; i ++) {
t[k].name[i] = text[i];
}
t[k].name[i] = text[left + j];
strcat(t[k].name, text + right + 1);
}
// 正则匹配
for (i = 0; i < n; i ++) {
for (j = flag = 0; j < count; j ++) {
if (strcasecmp(strs[i].name, t[j].name) == 0) {
flag = 1;
break;
}
}
if (flag) {
printf("%d %s\n", i + 1, strs[i].name);
}
}
}
}
return 0;
}
/**************************************************************
Problem: 1165
User: wangzhengyi
Language: C
Result: Accepted
Time:0 ms
Memory:948 kb
****************************************************************/