Java 7之多线程并发容器 - ArrayBlockingQueue(三)

2014-11-24 02:36:22 · 作者: · 浏览: 2
turned by next call to next // 上一次调用next()返回的元素 private E lastItem; // Element returned by last call to next // 上一次调用next()返回的元素的索引 private int lastRet; // Index of last element returned, or -1 if none Itr() { final ReentrantLock lock = ArrayBlockingQueue.this.lock; lock.lock(); try { lastRet = -1; if ((remaining = count) > 0) nextItem = itemAt(nextIndex = takeIndex); } finally { lock.unlock(); } } public boolean hasNext() { return remaining > 0; } public E next() { // 获取阻塞队列的锁 final ReentrantLock lock = ArrayBlockingQueue.this.lock; lock.lock(); try { // 若“剩余元素<=0”,则抛出异常。 if (remaining <= 0) throw new NoSuchElementException(); lastRet = nextIndex; // 获取第nextIndex位置的元素 E x = itemAt(nextIndex); // check for fresher value if (x == null) { x = nextItem; // we are forced to report old value lastItem = null; // but ensure remove fails } else lastItem = x; while (--remaining > 0 && // skip over nulls (nextItem = itemAt(nextIndex = inc(nextIndex))) == null) ; return x; } finally { lock.unlock(); } } public void remove() { final ReentrantLock lock = ArrayBlockingQueue.this.lock; lock.lock(); try { int i = lastRet; if (i == -1) throw new IllegalStateException(); lastRet = -1; E x = lastItem; lastItem = null; // only remove if item still at index if (x != null && x == items[i]) { boolean removingHead = (i == takeIndex); removeAt(i); if (!removingHead) nextIndex = dec(nextIndex); } } finally { lock.unlock(); } } }