高精度运算(运算符重载)(三)

2014-11-24 03:18:25 · 作者: · 浏览: 2
typedef long long huge; struct BigInt { int Len; int Data[Capacity]; BigInt() : Len(0) {} BigInt (const BigInt &V) : Len(V.Len) { memcpy (Data, V.Data, Len*sizeof*Data); } BigInt(int V) : Len(0) { for(; V>0; V/=Base) Data[Len++]=V%Base; } BigInt &operator=(const BigInt &V) { Len=V.Len; memcpy(Data, V.Data, Len*sizeof*Data); return *this; } int &operator[] (int Index) { return Data[Index]; } int operator[] (int Index) const { return Data[Index]; } }; int compare(const BigInt &A, const BigInt &B) { if(A.Len!=B.Len) return A.Len>B.Len 1:-1; int i; for(i=A.Len-1; i>=0 && A[i]==B[i]; i--); if(i<0)return 0; return A[i]>B[i] 1:-1; } BigInt operator + (const BigInt &A,const BigInt &B) { int i,Carry(0); BigInt R; for(i=0; i0; i++) { if(i
0&&R[R.Len-1]==0) R.Len--; return R; } BigInt operator * (const BigInt &A,const BigInt &B) { int i; huge Carry(0); BigInt R; for(i=0; i0; i++) { if(i>(istream &In,BigInt &V) { char Ch; for(V=0; In>>Ch;) { V=V*10+(Ch-'0'); if(In.peek()<=' ') break; } return In; } ostream &operator<<(ostream &Out,const BigInt &V) { int i; Out<<(V.Len==0 0:V[V.Len-1]); for(i=V.Len-2; i>=0; i--) for(int j=Base/10; j>0; j/=10) Out<>a>>b; cout<<"+"<0) cout<<"-"<
\