Harry Potter and the Forbidden Forest
Time Limit: 5000/3000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1155 Accepted Submission(s): 404
The FZ http://www.2cto.com/kf/ware/vc/" target="_blank" class="keylink">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"brush:java;">3 4 5 0 1 3 0 0 2 1 0 1 2 1 1 1 3 1 1 2 3 3 1 6 7 0 1 1 0 0 2 1 0 0 3 1 0 1 4 1 0 2 4 1 0 3 5 1 0 4 5 2 0 3 6 0 1 1 0 0 1 2 0 1 1 1 1 1 2 1 0 1 2 1 0 2 1 1 1
Sample Output
Case 1: 3 Case 2: 2 Case 3: 2 题意:求割边最少的最小割, 解题思路:在建图时,每个边权乘以一个大的数,然后加1,求出最大流取模,顺便就可以得到边数。 代码:/* *********************************************** Author :xianxingwuguan Created Time :2014-1-25 12:19:41 File Name :3.cpp ************************************************ */ #pragma comment(linker, "/STACK:102400000,102400000") #include#include #include #include #include #include #include #include