IO操作之使用zip包压缩和解压缩文件 (三)

2014-11-24 10:09:13 · 作者: · 浏览: 1
putStream类
* 当我们需要解压缩多个文件的时候,ZipEntry就无法使用了,
* 如果想操作更加复杂的压缩文件,我们就必须使用ZipInputStream类
* */
public static void ZipContraMultiFile(String zippath ,String outzippath){
try {
File file = new File(zippath);
File outFile = null;
ZipFile zipFile = new ZipFile(file);
ZipInputStream zipInput = new ZipInputStream(new FileInputStream(file));
ZipEntry entry = null;
InputStream input = null;
OutputStream output = null;
while((entry = zipInput.getNextEntry()) != null){
System.out.println("解压缩" + entry.getName() + "文件");
outFile = new File(outzippath + File.separator + entry.getName());
if(!outFile.getParentFile().exists()){
outFile.getParentFile().mkdir();
}
if(!outFile.exists()){
outFile.createNewFile();
}
input = zipFile.getInputStream(entry);
output = new FileOutputStream(outFile);
int temp = 0;
while((temp = input.read()) != -1){
output.write(temp);
}
input.close();
output.close();
}
} catch (Exception e) {
e.printStackTrace();
}
}应用:
[java]
ZipContraMultiFile("f:/zippath.zip", "d:/");
ZipContraMultiFile("d:/hello.zip", "d:/");

ZipContraMultiFile("f:/zippath.zip", "d:/");
ZipContraMultiFile("d:/hello.zip", "d:/");