问题
面试时经常会问起字符串比较相关的问题,
总结一下,大体是如下几个:
1.字符串比较时用的什么方法,内部实现如何
2.hashcode的作用,以及重写equal方法,为什么要重写hashcode方法
现在对以上几个问题,彻底做一个研究和小结.
PS:本文使用jdk1.7
解析
1.Object类 的equals 方法
* Indicates whether some other object is "equal to" this one. ** The {@code equals} method implements an equivalence relation * on non-null object references: *
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*
- It is reflexive: for any non-null reference value * {@code x}, {@code x.equals(x)} should return * {@code true}. *
- It is symmetric: for any non-null reference values * {@code x} and {@code y}, {@code x.equals(y)} * should return {@code true} if and only if * {@code y.equals(x)} returns {@code true}. *
- It is transitive: for any non-null reference values * {@code x}, {@code y}, and {@code z}, if * {@code x.equals(y)} returns {@code true} and * {@code y.equals(z)} returns {@code true}, then * {@code x.equals(z)} should return {@code true}. *
- It is consistent: for any non-null reference values * {@code x} and {@code y}, multiple invocations of * {@code x.equals(y)} consistently return {@code true} * or consistently return {@code false}, provided no * information used in {@code equals} comparisons on the * objects is modified. *
- For any non-null reference value {@code x}, * {@code x.equals(null)} should return {@code false}. *
* The {@code equals} method for class {@code Object} implements * the most discriminating possible equivalence relation on objects; * that is, for any non-null reference values {@code x} and * {@code y}, this method returns {@code true} if and only * if {@code x} and {@code y} refer to the same object * ({@code x == y} has the value {@code true}). *
* Note that it is generally necessary to override the {@code hashCode} * method whenever this method is overridden, so as to maintain the * general contract for the {@code hashCode} method, which states * that equal objects must have equal hash codes. * * @param obj the reference object with which to compare. * @return {@code true} if this object is the same as the obj * argument; {@code false} otherwise. * @see #hashCode() * @see java.util.HashMap */ public boolean equals(Object obj) { return (this == obj); } /** * Indicates whether some other object is "equal to" this one. *
* The {@code equals} method implements an equivalence relation * on non-null object references: *
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*
- It is reflexive: for any non-null reference value * {@code x}, {@code x.equals(x)} should return * {@code true}. *
- It is symmetric: for any non-null reference values * {@code x} and {@code y}, {@code x.equals(y)} * should return {@code true} if and only if * {@code y.equals(x)} returns {@code true}. *
- It is transitive: for any non-null reference values * {@code x}, {@code y}, and {@code z}, if * {@code x.equals(y)} returns {@code true} and * {@code y.equals(z)} returns {@code true}, then * {@code x.equals(z)} should return {@code true}. *
- It is consistent: for any non-null reference values * {@code x} and {@code y}, multiple invocations of * {@code x.equals(y)} consistently return {@code true} * or consistently return {@code false}, provided no * information used in {@code equals} comparisons on the * objects is modified. *
- For any non-null reference value {@code x}, * {@code x.equals(null)} should return {@code false}. *
* The {@code equals} method for class {@code Object} implements * the most discriminating possible equivalence relation on objects;