POJ 3686 The Windy's KM算法 (二)

2014-11-24 11:06:32 · 作者: · 浏览: 1
memset(visx, 0, sizeof(visx));
memset(visy, 0, sizeof(visy));
if(find(x)) break;
int d = INF;
for(int i = 1; i <= ny; i++)
if(!visy[i]) d = min(d, slack[i]);
if(d == INF) return -1;
for(int i = 1; i <= nx; i++)
if(visx[i]) lx[i] -=d;
for(int i = 1; i <= ny; i++)
if(visy[i]) ly[i] += d;
else slack[i] -= d;
}
}
int tp = 0;
for(int i = 1; i <= ny; i++)
if(linky[i] != -1) tp += w[linky[i]][i] - 5000000;
return -tp;
}
int a[MAXN][MAXN];
int main()
{
int T;
scanf("%d", &T);
while(T--)
{
memset(w, 0, sizeof(w));
scanf("%d%d", &n, &m);
for(int i = 1; i <= n; i++)
for(int j = 1; j <= m; j++)
scanf("%d", &a[i][j]);
for(int i = 1; i <= n; i++)
for(int j = 1; j <= m; j++)
for(int k = 1; k <= n; k++)
w[i][(j - 1) * n + k] = 5000000 - a[i][j] * k;
nx = n;www.2cto.com
ny = n * m;
double ans = 1.0 * KM() / n;
printf("%f\n", ans);
}
return 0;
}



作者:sdj222555