最小费用最大流之 zkw费用流与普通费用流 (四)

2014-11-24 11:08:43 · 作者: · 浏览: 3
AXN];
int ans, cost, src, des, n;
void init()
{
memset(head, -1, sizeof(head));
e = 0;
ans = cost = 0;
}
void add(int u, int v, int cap, int cost)
{
edge[e].v = v;
edge[e].cap = cap;
edge[e].cost = cost;
edge[e].re = e + 1;
edge[e].next = head[u];
head[u] = e++;
edge[e].v = u;
edge[e].cap = 0;
edge[e].cost = -cost;
edge[e].re = e - 1;
edge[e].next = head[v];
head[v] = e++;
}
int aug(int u, int f)
{
if(u == des)
{
ans += cost * f;
return f;
}
vis[u] = 1;
int tmp = f;
for(int i = head[u]; i != -1; i = edge[i].next)
if(edge[i].cap && !edge[i].cost && !vis[edge[i].v])
{
int delta = aug(edge[i].v, tmp < edge[i].cap tmp : edge[i].cap);
edge[i].cap -= delta;
edge[edge[i].re].cap += delta;
tmp -= delta;
if(!tmp) return f;
}
return f - tmp;
}
bool modlabel()
{
for(int i = 0; i <= n; i++) d[i] = INF;
d[des] = 0;
dequeQ;
Q.push_back(des);
while(!Q.empty())
{
int u = Q.front(), tmp;
Q.pop_front();
for(int i = head[u]; i != -1; i = edge[i].next)
if(edge[edge[i].re].cap && (tmp = d[u] - edge[i].cost) < d[edge[i].v])
(d[edge[i].v] = tmp) <= d[Q.empty() src : Q.front()] Q.push_front(edge[i].v) : Q.push_back(edge[i].v);
}
for(int u = 1; u <= n; u++)
for(int i = head[u]; i != -1; i = edge[i].next)
edge[i].cost += d[edge[i].v] - d[u];
cost += d[src];
return d[src] < INF;
}
void costflow()
{
while(modlabel())
{
do
{
memset(vis, 0, sizeof(vis));
}while(aug(src, INF));
}
}
int nt, m;
struct point
{
int x, y;
}p[MAXN], h[MAXN];
int dis[MAXN][MAXN];
char s[MAXN][MAXN];
int main()
{
while(scanf("%d%d", &m, &nt) != EOF)
{
if(m == 0 && nt == 0) break;
for(int i = 0; i < m; i++)
scanf("%s", s[i]);
int hcnt = 0, pcnt = 0;
for(int i = 0; i < m; i++)
for(int j = 0; j < nt; j++)
{
if(s[i][j] == 'H')
{
hcnt++;
h[hcnt].x = i;
h[hcnt].y = j;
}
else if(s[i][j] == 'm')
{
pcnt++;
p[pcnt].x = i;
p[pcnt].y = j;
}
}
for(int i = 1; i <= pcnt; i++)
for(int j = 1; j <= hcnt; j++)
dis[i][j] = abs(p[i].x - h[j].x) + abs(p[i].y - h[j].y);
init();
n = hcnt + pcnt + 2;
src = hcnt + pcnt + 1;
des = n;
for(int i = 1; i <= pcnt; i++)
for(int j = 1; j <= hcnt; j++)
add(i, j + pcnt, 1, dis[i][j]);
for(int i = 1; i <= pcnt; i++)
add(src, i, 1, 0);
for(int i = 1; i <= hcnt; i++)
add(i + pcnt, des, 1, 0);
costflow();
printf("%d\n", ans);
}
return 0;
}
作者:sdj222555