生成等宽字距字符串的算法 (一)

2014-11-24 11:22:28 · 作者: · 浏览: 5

我们知道,在很多字体下面,每个英文字母的宽度是不一样的,就拿W和I来讲,W的宽度要大于I的宽度(字体的宽度),所以有时候我们会不太喜欢这样的定义。


以下我以Windows下默认的文件名称为例,我对比发现,等宽字符可以分成下面5组:

public static final char [] charsA = new char[]{'A','B','C','K','X'};
public static final char [] charsD = new char[]{'D','G','H','U'};
public static final char [] charsN = new char[]{'N','O','Q'};
public static final char [] charsF = new char[]{'F','L'};
public static final char [] charsE = new char[]{'E','P','S','T','Y','Z'};


每一组字符时等宽的,我们要想他们组合起来的字符串也是等宽的,那也有很多种情况,不过方法都是类似的,我以5个字母的字符串为例。


就是每个数组各取一个字符,例如各取第一个字符和各取第二个字符,分别是ADNFE和BGOLP,这两个字符串是等宽的。


下面给出Java语言版的算法,

[java]
public static final char [] charsA = new char[]{'A','B','C','K','X'};
public static final char [] charsD = new char[]{'D','G','H','U'};
public static final char [] charsN = new char[]{'N','O','Q'};
public static final char [] charsF = new char[]{'F','L'};
public static final char [] charsE = new char[]{'E','P','S','T','Y','Z'};


public static void main(String[] args) {

for(int i=0;i<100;i++){
System.out.println(getRandomStr());
}
}

public static String getRandomStr(){
StringBuffer strbuf = new StringBuffer();

int orgIntArray[] = { 1, 2, 3, 4, 5 };
int resultArray[] = zolltyRandom(orgIntArray);
int i = 0;
for(int j=0;j switch(resultArray[j]){
case 1:{
i = (int) (Math.random()*5);
strbuf.append(charsA[i]);
break;
}
case 2:{
i = (int) (Math.random()*4);
strbuf.append(charsD[i]);
break;
}
case 3:{
i = (int) (Math.random()*3);
strbuf.append(charsN[i]);
break;
}
case 4:{
i = (int) (Math.random()*2);
strbuf.append(charsF[i]);
break;
}
case 5:{
i = (int) (Math.random()*6);
strbuf.append(charsE[i]);
break;
}
}
}

return strbuf.toString();
}


/**
* 将原始数组重新随机排序(=洗牌)
*
* @param orgIntArray
* 例如{ 0, 1, 2, 3, 4, 5, 6, 7 }
* @return 排列后的数组
* @author zollty
*/
public static int[] zolltyRandom(int[] orgIntArray) {

Random rand = new Random();

int pos, temp2;

int returnValue[] = new int[orgIntArray.length];

for (int i = 0, r = orgIntArray.length; i < orgIntArray.length - 1; i++, r--) {
pos = Math.abs(rand.nextInt()) % r;

returnValue[i] = orgIntArray[pos];

// [pos]已使用,与最后那个未使用的交换
temp2 = orgIntArray[pos];
orgIntArray[pos] = orgIntArray[r - 1];
orgIntArray[r - 1] = temp2;
}

returnValue[orgIntArray.length - 1] = orgIntArray[0];

return returnValue;
}

public static final char [] charsA = new char[]{'A','B','C','K','X'};
public static final char [] charsD = new char[]{'D','G','H','U'};
public static final char [] charsN = new char[]{'N','O','Q'};
public static final char [] charsF = new char[]{'F','L'};
public static final char [] charsE = new char[]{'E','P','S','T','Y','Z'};


public static void main(String[] args) {

for(int i=0;i<100;i++){
System.out.println(getRandomStr());
}
}

public static String getRandomStr(){
StringBuffer strbuf = new StringBuffer();

int orgIntArray[] = { 1, 2, 3, 4, 5 };
int resultArray[