访问V$LOCK视图Oracle 11g出现性能问题(二)

2014-11-24 19:00:20 · 作者: · 浏览: 56
1 |



  | 6 | VIEW | GV$_LOCK | 10 | 780 | 0 (0)| 00:00:01 |



  | 7 | UNION-ALL | | | | | |



  |* 8 | FILTER | | | | | |



  | 9 | VIEW | GV$_LOCK1 | 2 | 156 | 0 (0)| 00:00:01 |



  | 10 | UNION-ALL | | | | | |



  |* 11 | FIXED TABLE FULL| X$KDNSSF | 1 | 102 | 0 (0)| 00:00:01 |



  |* 12 | FIXED TABLE FULL| X$KSQEQ | 1 | 102 | 0 (0)| 00:00:01 |



  |* 13 | FIXED TABLE FULL | X$KTADM | 1 | 102 | 0 (0)| 00:00:01 |



  |* 14 | FIXED TABLE FULL | X$KTATRFIL | 1 | 102 | 0 (0)| 00:00:01 |



  |* 15 | FIXED TABLE FULL | X$KTATRFSL | 1 | 102 | 0 (0)| 00:00:01 |



  |* 16 | FIXED TABLE FULL | X$KTATL | 1 | 102 | 0 (0)| 00:00:01 |



  |* 17 | FIXED TABLE FULL | X$KTSTUSC | 1 | 102 | 0 (0)| 00:00:01 |



  |* 18 | FIXED TABLE FULL | X$KTSTUSS | 1 | 102 | 0 (0)| 00:00:01 |



  |* 19 | FIXED TABLE FULL | X$KTSTUSG | 1 | 102 | 0 (0)| 00:00:01 |



  |* 20 | FIXED TABLE FULL | X$KTCXB | 1 | 102 | 0 (0)| 00:00:01 |



  -------------------------------------------------------------------------------------



  Predicate Information (identified by operation id):



  ---------------------------------------------------



  1 -access("SADDR"="S"."ADDR" AND TO_CHAR(USERENV('INSTANCE'))||RAWTOHEX("



  RADDR")=TO_CHAR("R"."INST_ID")||RAWTOHEX("R"."ADDR"))



  3 -filter("S"."INST_ID"=USERENV('INSTANCE'))



  5 -filter("R"."KSQRSIDT"<>'MR')



  8 - filter(USERENV('INSTANCE') IS NOT NULL)



  11 -filter(("KSQLKMOD"<>0 OR "KSQLKREQ"<>0) AND



  "INST_ID"=USERENV('INSTANCE') AND BITAND("KSSOBFLG",1)<>0)



  12 -filter(("KSQLKMOD"<>0 OR "KSQLKREQ"<>0) AND



  "INST_ID"=USERENV('INSTANCE') AND BITAND("KSSOBFLG",1)<>0)



  13 -filter(("KSQLKMOD"<>0 OR "KSQLKREQ"<>0) AND



  "INST_ID"=USERENV('INSTANCE') AND BITAND("KSSOBFLG",1)<>0)



  14 -filter(("KSQLKMOD"<>0 OR "KSQLKREQ"<>0) AND



  "INST_ID"=USERENV('INSTANCE') AND BITAND("KSSOBFLG",1)<>0)



  15 -filter(("KSQLKMOD"<>0 OR "KSQLKREQ"<>0) AND



  "INST_ID"=USERENV('INSTANCE') AND BITAND("KSSOBFLG",1)<>0)



  16 -filter(("KSQLKMOD"<>0 OR "KSQLKREQ"<>0) AND



  "INST_ID"=USERENV('INSTANCE') AND BITAND("KSSOBFLG",1)<>0)



  17 - filter(("KSQLKMOD"<>0 OR "KSQLKREQ"<>0) AND



  "INST_ID"=USERENV('INSTANCE') AND BITAND("KSSOBFLG",1)<>0)



  18 -filter(("KSQLKMOD"<>0 OR "KSQLKREQ"<>0) AND



  "INST_ID"=USERENV('INSTANCE') AND BITAND("KSSOBFLG",1)<>0)



  19 - filter(("KSQLKMOD"<>0 OR "KSQLKREQ"<>0) AND



  "INST_ID"=USERENV('INSTANCE') AND BITAND("KSSOBFLG",1)<>0)



  20 -filter(("KSQLKMOD"<>0 OR "KSQLKREQ"<>0) AND



  "INST_ID"=USERENV('INSTANCE') AND BITAND("KSSPAFLG",1)<>0)



  56 rows selected.



  SQL> select count(*) from X$KSUSE;



  COUNT(*)



  ----------



  4528



  SQL> select count(*) from X$KSQRS;



  COUNT(*)



  ----------



  20144



  显然导致查询缓慢以及读取临时空间的问题原因在于执行计划的错误,而执行计划的错误在于统计信息不准确。



  解决方法有两种,一种是使用RBO读取V$LOCK视图,另一种是收集V$视图的统计信息,是的Oracle获取正确的执行计划:



  SQL> select /*+ rule */ * from v$lock where type != 'MR';



  ADDR KADDR SID TY ID1 ID2 LMODE REQUEST CTIME BLOCK



  ---------------- ---------------- ---- -- -------- ---- ----- ------- ----- -----



  0000000C5A6A4A20 0000000C5A6A4A78 2831 PW 1 0 3 0 9861 0



  0000000C5A6A3790 0000000C5A6A37E8 3963 TS 16 1 3 0 8444 0



  0000000C5A6A2518 0000000C5A6A2570 3963 TS 3 1 3 0 9863 0



  00007FEEB24CC490 00007FEEB24CC4F0 1144 TM 75580 0 4 0 2615 0



  0000000C5A6A6E30 0000000C5A6A6E88 1144 AE 0 1 4 0 2615 0



  0000000C44D8FF08 0000000C44D8FF80 1144 TX 12124184 2594 6 0 2615 0



  00007FEEB24CC490 00007FEEB24CC4F0 1144 TM 28 0 3 0 2615 0



  0000000C5A6AA850 0000000C5A6AA8A8 1144 TO 5124 1 3 0 6979 0



  00007FEEB24CC490 00007FEEB24CC4F0 1144 TM 75584 0 4 0 2615 0



  0000000C5A6AA5B0 0000000C5A6AA608 1144 AE 100 0 4 0 6997 0



  0000000C5A6A6018 0000000C5A6A6070 1990 AE 100 0 4 0 1027 0



  0000000C5A6A4860 0000000C5A6A48B8 1 AE 100 0 4 0 9861 0



  0000000C5A6A4940 0000000C5A6A4998 1983 KD 0 0 6 0 9862 0



  00000