1561: (More) Multiplication(模似)(二)

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Input

The input contains one or more tests. Each test contains two positive integers, A and B, such that 1 ≤ A ≤ 9999 and 1 ≤ B ≤ 9999. The last data set will be followed by a line containing 0 0.

Output

For each data set, produce the grid that illustrates how to multiply the two numbers using the lattice multiplication technique.

Sample Input

345 56
12 27
1 68
9999 7
3 3
0 0

Sample Output

+---------------+
|   3   4   5   |
| +---+---+---+ |
| |1 /|2 /|2 /| |
| | / | / | / |5|
|1|/ 5|/ 0|/ 5| |
| +---+---+---+ |
|/|1 /|2 /|3 /| |
| | / | / | / |6|
|9|/ 8|/ 4|/ 0| |
| +---+---+---+ |
|/ 3 / 2 / 0    |
+---------------+
+-----------+
|   1   2   |
| +---+---+ |
| |0 /|0 /| |
| | / | / |2|
| |/ 2|/ 4| |
| +---+---+ |
| |0 /|1 /| |
| | / | / |7|
|3|/ 7|/ 4| |
| +---+---+ |
|/ 2 / 4    |
+-----------+
+-------+
|   1   |
| +---+ |
| |0 /| |
| | / |6|
| |/ 6| |
| +---+ |
| |0 /| |
| | / |8|
|6|/ 8| |
| +---+ |
|/ 8    |
+-------+
+-------------------+
|   9   9   9   9   |
| +---+---+---+---+ |
| |6 /|6 /|6 /|6 /| |
| | / | / | / | / |7|
|6|/ 3|/ 3|/ 3|/ 3| |
| +---+---+---+---+ |
|/ 9 / 9 / 9 / 3    |
+-------------------+
+-------+
|   3   |
| +---+ |
| |0 /| |
| | / |3|
| |/ 9| |
| +---+ |
|  9    |
+-------+

HINT

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The tables must be formatted precisely as outlined by the rules and examples provided. Mistakes that involve solely errant whitespace will be categorized as Presentation Error; all other errors will be reported as Wrong Answer.

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#include
  
   
const int N =100;

int main()
{
    int A,B,C,a[N],b[N],c[N],lenA,lenB,lenC,flag;
    while(scanf("%d%d",&A,&B)>0)
    {
        if(A==0&&B==0)
            break;
        C=A*B;
        lenA=lenB=lenC=0;
        while(A)
        {
            a[++lenA]=A%10; A/=10;
        }
        while(B)
        {
            b[++lenB]=B%10; B/=10;
        }
        while(C)
        {
            c[++lenC]=C%10; C/=10;
        }
        for(int i=1,j=lenA;i0;i--)
        for(int j=1;j<=4;j++)
        {
            printf("|");
            if(j!=2)
            {
                if(j!=4||lenC-lenA
   
    i)printf("/"); else printf(" "); } if(j==1) { printf("+"); for(int e=1;e<=lenA;e++) printf("---+"); printf(" |\n"); } else if(j==2) { for(int e=1;e<=lenA;e++) printf("|%d /",(a[e]*b[i])/10); printf("| |\n"); } else if(j==3) { for(int e=1;e<=lenA;e++) printf("| / "); printf("|%d|\n",b[i]); } else { for(int e=1;e<=lenA;e++) printf("|/ %d",(a[e]*b[i])%10); printf("| |\n"); } } printf("| +"); for(int e=1;e<=lenA;e++) printf("---+"); printf(" |\n"); printf("|"); if(flag>lenA) printf("/"); else printf(" "); while(lenC) { printf(" %d ",c[lenC--]); if(lenC) printf("/"); } printf(" |\n"); printf("+-"); for(int i=1;i<=lenA;i++) printf("----"); printf("--+\n"); } } 
   
   
   
  

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