n also be determined. So, there can be many options, but you need at least 2 rats.
题意:其实就是求n个普通液体和一瓶毒液，求最少需要几只老鼠同时实验，找出毒液
思路：其实就是能有几个2组成，不够的也要算
#include
#include
#include
#include
using namespace std; int main() { int t; int cas = 1; long long n, ans; scanf("%d", &t); while (t--) { scanf("%lld", &n); ans = 0; while (n) { ans++; n /= 2; } printf("Case %d: ", cas++); printf("%lld\n", ans); } return 0; }