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一步一步写算法(之排序二叉树删除-2) (一)
2014-11-23 23:36:32 来源: 作者: 【 】 浏览:7
Tags:步一步 算法 排序 删除

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2.4 删除节点的左右子树都存在,此时又会分成两种情形

1)左节点是当前左子树的最大节点,此时只需要用左节点代替根节点即可

/*

*

* 10 ======> 6

* / \ / \

* 6 15 5 15

* /

* 5

*/

/*

*

* 10 ======> 6

* / \ / \

* 6 15 5 15

* /

* 5

*/ 代码该怎么编写呢?

STATUS delete_node_from_tree(TREE_NODE** ppTreeNode, int data)

{

TREE_NODE* pTreeNode;

TREE_NODE* pLeftMax;

if(NULL == ppTreeNode || NULL == *ppTreeNode)

return FALSE;

pTreeNode = find_data_in_tree_node(*ppTreeNode, data);

if(NULL == pTreeNode)

return FALSE;

if(*ppTreeNode == pTreeNode){

if(NULL == pTreeNode->left_child && NULL == pTreeNode->right_child){

*ppTreeNode = NULL;

}else if(NULL != pTreeNode->left_child && NULL == pTreeNode->right_child){

*ppTreeNode = pTreeNode->left_child;

pTreeNode->left_child->parent = NULL;

}else if(NULL == pTreeNode->left_child && NULL != pTreeNode->right_child){

*ppTreeNode = pTreeNode->right_child;

pTreeNode->right_child->parent = NULL;

}else{

pLeftMax = find_max_node(pTreeNode->left_child);

if(pLeftMax == pTreeNode->left_child){

*ppTreeNode = pTreeNode->left_child;

(*ppTreeNode)->right_child = pTreeNode->right_child;

(*ppTreeNode)->right_child->parent = *ppTreeNode;

(*ppTreeNode)->parent = NULL;

}

}

free(pTreeNode);

return TRUE;

}

return TRUE;

}

STATUS delete_node_from_tree(TREE_NODE** ppTreeNode, int data)

{

TREE_NODE* pTreeNode;

TREE_NODE* pLeftMax;

if(NULL == ppTreeNode || NULL == *ppTreeNode)

return FALSE;

pTreeNode = find_data_in_tree_node(*ppTreeNode, data);

if(NULL == pTreeNode)

return FALSE;

if(*ppTreeNode == pTreeNode){

if(NULL == pTreeNode->left_child && NULL == pTreeNode->right_child){

*ppTreeNode = NULL;

}else if(NULL != pTreeNode->left_child && NULL == pTreeNode->right_child){

*ppTreeNode = pTreeNode->left_child;

pTreeNode->left_child->parent = NULL;

}else if(NULL == pTreeNode->left_child && NULL != pTreeNode->right_child){

*ppTreeNode = pTreeNode->right_child;

pTreeNode->right_child->parent = NULL;

}else{

pLeftMax = find_max_node(pTreeNode->left_child);

if(pLeftMax == pTreeNode->left_child){

*ppTreeNode = pTreeNode->left_child;

(*ppTreeNode)->right_child = pTreeNode->right_child;

(*ppTreeNode)->right_child->parent = *ppTreeNode;

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