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HDU 2163 Palindromes
2015-07-20 18:02:35 来源: 作者: 【 】 浏览:3
Tags:HDU 2163 Palindromes

Palindromes

Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 2949 Accepted Submission(s): 1723


Problem Description Write a program to determine whether a word is a palindrome. A palindrome is a sequence of characters that is identical to the string when the characters are placed in reverse order. For example, the following strings are palindromes: “ABCCBA”, “A”, and “AMA”. The following strings are not palindromes: “HELLO”, “ABAB” and “PPA”.

Input The input file will consist of up to 100 lines, where each line contains at least 1 and at most 52 characters. Your program should stop processing the input when the input string equals “STOP”. You may assume that input file consists of exclusively uppercase letters; no lowercase letters, punctuation marks, digits, or whitespace will be included within each word.

Output A single line of output should be generated for each string. The line should include “#”, followed by the problem number, followed by a colon and a space, followed by the string “YES” or “NO”.

Sample Input
ABCCBA
A
HELLO
ABAB
AMA
ABAB
PPA
STOP

Sample Output
#1: YES
#2: YES
#3: NO
#4: NO
#5: YES
#6: NO
#7: NO


我想shi的心都有了,那天考试连A三次都没过,思路也没啥问题啊!事后突然发现大写的O不知怎么的被写写成小写的了。哎,不然名次就上升好几名了


#include
  
   
#include
   
     char a[60]; int main() { int t,len,i,j,m=1,b,c,d; while(scanf("%s",a)!=EOF) { if(!strcmp(a, "STOP")) break; printf("#%d: ",m++); b=c=d=0; len=strlen(a); if(len==1) {printf("YES\n");continue;} t=len/2; if(len%2==0) { for(i=0;i
    
     





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