Hello World!
Time Limit: 2000/1000 MS (
Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 465 Accepted Submission(s): 172
Problem Description Your task is to print ... er ... "Hello World" ... in a fantastic way -- using a beautiful font.
I've sent you a nice font for you to use, but I'm too busy to tell you how. Can you help yourself?
Input The first line contains a single integer T (T <= 20), the number of test cases.
Each case begins with an integer C (1 <= C <= 80) in a single line, then each of the following C lines contains five two-digit numbers in hex (letters will be in uppercase). Don't ask me what they mean, I'm too busy...
Output For each test case, print the case number in the first line, then followed by a blank line.
After that, print all T characters. Use a single blank column of spaces between two consecutive characters. Each line should have exactly 6C-1 character (again, don't ask me why).
Don't forget to print another blank line after the output of each test case.
Sample Input
2
11
7F 08 08 08 7F
38 54 54 54 18
00 41 7F 40 00
00 41 7F 40 00
38 44 44 44 38
00 00 00 00 00
3F 40 38 40 3F
38 44 44 44 38
7C 08 04 04 08
00 41 7F 40 00
38 44 44 48 7F
5
14 08 3E 08 14
04 02 01 02 04
40 40 40 40 40
04 02 01 02 04
14 08 3E 08 14
Sample Output
Case 1:
# # ## ## # # ## #
# # # # # # # #
# # ### # # ### # # ### # ## # ## #
##### # # # # # # # # # # # ## # # # ##
# # ##### # # # # # # # # # # # # #
# # # # # # # # # # # # # # # #
# # ### ### ### ### # # ### # ### ####
Case 2:
# #
# # # # # #
# # # # # # # # # #
### ###
# # # # # #
# #
#####
Source 2009 Asia Regional Ningbo Online
题意：前面基本上都是废话，主要是让你自己看输入输出找规律。
题解：坑人的地方是这题输出的时候其实是7行，而不是8行！！！因此PE了N次！
#include
#define maxn 482
char map[8][maxn];
bool isPrint[8];
void getIsPrint(int n)
{
for(int i = 0; i < 7; ++i){
isPrint[i] = n & 1;
n >>= 1;
}
}
int main()
{
//freopen("stdout.txt", "w", stdout);
int t, n, arr[5], i, j, id, k, cas = 1;
scanf("%d", &t);
while(t--){
scanf("%d", &n);
for(i = id = 0; i < n; ++i){
for(j = 0; j < 5; ++j, ++id){
scanf("%X", arr + j);
getIsPrint(arr[j]);
for(k = 0; k < 7; ++k)
if(isPrint[k]) map[k][id] = '#';
else map[k][id] = ' ';
}
if(i != n - 1){
for(k = 0; k < 7; ++k)
map[k][id] = ' ';
++id;
}
}
printf("Case %d:\n\n", cas++);
for(k = 0; k < 7; ++k){
map[k][id] = '\0';
printf("%s\n", map[k]);
}
printf("\n");
}
return 0;
}