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HDU 1051: Wooden Sticks(贪心)
2015-07-20 18:07:30 来源: 作者: 【 】 浏览:8
Tags:HDU 1051 Wooden Sticks 贪心

Wooden Sticks



Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 11244 Accepted Submission(s): 4627


Problem Description There is a pile of n wooden sticks. The length and weight of each stick are known in advance. The sticks are to be processed by a woodworking machine in one by one fashion. It needs some time, called setup time, for the machine to prepare processing a stick. The setup times are associated with cleaning operations and changing tools and shapes in the machine. The setup times of the woodworking machine are given as follows:

(a) The setup time for the first wooden stick is 1 minute.
(b) Right after processing a stick of length l and weight w , the machine will need no setup time for a stick of length l' and weight w' if l<=l' and w<=w'. Otherwise, it will need 1 minute for setup.

You are to find the minimum setup time to process a given pile of n wooden sticks. For example, if you have five sticks whose pairs of length and weight are (4,9), (5,2), (2,1), (3,5), and (1,4), then the minimum setup time should be 2 minutes since there is a sequence of pairs (1,4), (3,5), (4,9), (2,1), (5,2).

Input The input consists of T test cases. The number of test cases (T) is given in the first line of the input file. Each test case consists of two lines: The first line has an integer n , 1<=n<=5000, that represents the number of wooden sticks in the test case, and the second line contains n 2 positive integers l1, w1, l2, w2, ..., ln, wn, each of magnitude at most 10000 , where li and wi are the length and weight of the i th wooden stick, respectively. The 2n integers are delimited by one or more spaces.

Output The output should contain the minimum setup time in minutes, one per line.

Sample Input
3 
5 
4 9 5 2 2 1 3 5 1 4 
3 
2 2 1 1 2 2 
3 
1 3 2 2 3 1

Sample Output
2
1
3

题意是第一个3是3组数据, 然后一个5是5根棍子, 然后逐一输入其的长度和重量。。题目是问怎么做这些棍子用时最少,在做棍子时,若后一根棍子,长度和重量都大于前

一根,则不用加时间。。


想法。。

拿第一组数据来说。。

首先按长度以小到大排序:(1,4),(2,1),(3, 5), (4, 9),(5,2);

我们发现(2, 1)的重量太小, 而(5, 2)的长度太长。这样排结果为3;

其实这时,我们只要把不满足的先标记起来。。

则(1,4),(3,5),(4,9) ―――― (2,1), (5,2)

但我们这么排, 也就是题目给出的顺序,结果就为2;也就是最优。




#include
  
   
#include
   
     #include
    
      #include
     
       #include
      
        #include
       
         #include
        
          #include
         
           using namespace std; #define M 100500 struct node { int lenth; int weight; int k; } Q[M]; bool cmp ( node a, node b ) { if(a.lenth==b.lenth) return a.weight
          
           =t &&Q[j].k==1 ) { ans++; Q[j].k=0; t = Q[j].weight; } } printf("%d\n", n-ans); } return 0; } 
          
         
        
       
      
     
    
   
  







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