POJ_2503_Babelfish（map or 字典树） - c++编程基础

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POJ_2503_Babelfish（map or 字典树）

2015-07-24 05:00:51 来源: 作者: 【大中小】浏览:5次

Babelfish

Time Limit: 3000MS	?	Memory Limit: 65536K
Total Submissions: 34816	?	Accepted: 14908

Description

You have just moved from Waterloo to a big city. The people here speak an incomprehensible dialect of a foreign language. Fortunately, you have a dictionary to help you understand them.

Input

Input consists of up to 100,000 dictionary entries, followed by a blank line, followed by a message of up to 100,000 words. Each dictionary entry is a line containing an English word, followed by a space and a foreign language word. No foreign word appears more than once in the dictionary. The message is a sequence of words in the foreign language, one word on each line. Each word in the input is a sequence of at most 10 lowercase letters.

Output

Output is the message translated to English, one word per line. Foreign words not in the dictionary should be translated as "eh".

Sample Input

dog ogday
cat atcay
pig igpay
froot ootfray
loops oopslay

atcay
ittenkay
oopslay

Sample Output

cat
eh
loops

Hint

Huge input and output,scanf and printf are recommended.

Source

Waterloo local 2001.09.22

题意：就是对应翻译，如果没有找到翻译就输出“eh”。
分析：首选就想到了map去做，然后AC了。最近在做字典树的题目，于是用字典树也写了一遍。
题目链接：http://poj.org/problem?id=2503
map代码：

#include

#include #include #include #include using namespace std; const int MAX = 27 ; const int MAXN = 100000 + 5 ; map m; int num = 0 , len; char s[MAXN][MAX],str[MAXN]; int main(){ //freopen("liuchu.txt","r",stdin); while(gets(s[num])&&s[num][0]!='\0'){ len = strlen(s[num]); int first = 0, k = 0; for(int i=0;i
trie代码：

#include
         
          
#include
          
            #include
           
             #include
            
              using namespace std; typedef long long ll; const int MAX = 27 ; const int MAXN = 100000 + 5 ; struct trie{ int point; trie *next[MAX]; }; int number = 0 ; char s[MAXN][MAX],str[MAX]; trie *root=new trie; void createTrie(char *s,int n){ trie *p=root,*q; int len=strlen(s),pos; for(int i=0;i
             
              next[pos]==NULL){ q=new trie; for(int j=0;j
              
               next[j]=NULL; p->next[pos]=q; p=p->next[pos]; } else{ p=p->next[pos]; } } p->point=n; } int findTrie(char *s){ trie *p=root; int len=strlen(s),pos; for(int i=0;i
               
                next[pos]==NULL) return -1; p=p->next[pos]; } return p->point; } void delTrie(trie *Root){ for(int i=0;i
                
                 next[i]!=NULL) delTrie(Root->next[i]); } free(Root); } int main(){ //freopen("liuchu.txt","r",stdin); for(int i=0;i
                 
                  next[i]=NULL; while(gets(s[number])&&s[number][0]!='\0'){ int len=strlen(s[number]),k=0 ; bool judge=false; for(int i=0;i


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