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POJ 2386 Lake Counting
2015-07-24 05:33:31 来源: 作者: 【 】 浏览:5
Tags:POJ 2386 Lake Counting

Lake Counting
Time Limit: 1000MS Memory Limit: 65536K
Total Submissions: 19591 Accepted: 9848

Description

Due to recent rains, water has pooled in various places in Farmer John's field, which is represented by a rectangle of N x M (1 <= N <= 100; 1 <= M <= 100) squares. Each square contains either water ('W') or dry land ('.'). Farmer John would like to figure out how many ponds have formed in his field. A pond is a connected set of squares with water in them, where a square is considered adjacent to all eight of its neighbors.

Given a diagram of Farmer John's field, determine how many ponds he has.

Input

* Line 1: Two space-separated integers: N and M

* Lines 2..N+1: M characters per line representing one row of Farmer John's field. Each character is either 'W' or '.'. The characters do not have spaces between them.

Output

* Line 1: The number of ponds in Farmer John's field.

Sample Input

10 12
W........WW.
.WWW.....WWW
....WW...WW.
.........WW.
.........W..
..W......W..
.W.W.....WW.
W.W.W.....W.
.W.W......W.
..W.......W.

Sample Output

3


搜索水题,不解释!!!!!!!!

AC代码如下:

#include
  
   
#include
   
     int x[8]={0,1,1,1,0,-1,-1,-1}; int y[8]={-1,-1,0,1,1,1,0,-1}; int n,m; char b[105][105]; void sreach(int h,int z) { int i; b[h][z]='.'; for(i=0;i<8;i++) { if(b[h+x[i]][z+y[i]]=='W') sreach(h+x[i],z+y[i]); } } int main() { int i,j,cont; while(~scanf("%d %d",&n,&m)) { memset(b,0,sizeof(b)); cont=0; for(i=0;i
    
     


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