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模拟，每次进行操作时判断操作是否合法，合法才执行，否则跳过。每次一个token落地，判断一下是否有消除整行。

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#include 
  
   
#include 
   
     #include 
    
      using namespace std; /******* Token **********/ const int C[3] = {1, 2, 4}; const int T[3][4][4][2] = { {{{0, 0}, {0, 1}, {1, 0}, {1, 1}}, {}, {}, {}}, {{{0, 0}, {0, 1}, {0, 2}, {0, 3}}, {{0, 0}, {1, 0}, {2, 0}, {3, 0}}, {}, {}}, {{{0, 0}, {0, 1}, {1, 0}, {2, 0}}, {{0, 0}, {0, 1}, {0, 2}, {1, 2}}, {{0, 1}, {1, 1}, {2, 0}, {2, 1}}, {{0, 0}, {1, 0}, {1, 1}, {1, 2}}} }; void put (const int a[4][2]) { int g[4][4]; memset(g, 0, sizeof(g)); for (int i = 0; i < 4; i++) g[a[i][0]][a[i][1]] = 1; for (int i = 3; i >= 0; i--) { for (int j = 0; j < 4; j++) printf(%c, g[j][i] ? '#' : '.'); printf( ); } printf( ); } /************************/ const int maxn = 1005; int N, M, P, B[maxn], G[15][15]; char order[maxn]; bool judge (int x, int y, const int t[4][2]) { for (int i = 0; i < 4; i++) { int p = x + t[i][0]; int q = y + t[i][1]; if (G[p][q]) return false; } return true; } void tag (int x, int y, const int t[4][2]) { for (int i = 0; i < 4; i++) { int p = x + t[i][0]; int q = y + t[i][1]; G[p][q] = 1; } } void play(int t) { int x = 4, y = 9, c = 0; while (P < M) { if (order[P] == 'w') { if (judge(x, y, T[t][(c + 1) % C[t]])) c = (c + 1) % C[t]; } else if (order[P] == 'a') { if (judge(x - 1, y, T[t][c])) x = x - 1; } else if (order[P] == 's') { if (judge(x, y - 1, T[t][c])) y = y - 1; } else if (order[P] == 'd') { if (judge(x + 1, y, T[t][c])) x = x + 1; } P++; if (!judge(x, y - 1, T[t][c])) break; y = y - 1; } tag(x, y, T[t][c]); } int remove () { int ret = 0; for (int j = 1; j <= 9; j++) { bool flag = true; for (int i = 1; i <= 9; i++) { if (G[i][j] == 0) { flag = false; break; } } if (flag) { ret++; for (int x = j; x < 12; x++) { for (int i = 1; i <= 9; i++) G[i][x] = G[i][x+1]; } j--; } } return ret; } int solve () { scanf(%d%s, &N, order); P = 0; M = strlen(order); memset(G, 0, sizeof(G)); for (int i = 0; i < 15; i++) G[i][0] = G[0][i] = G[10][i] = -1; int ret = 0, t; for (int i = 1; i <= N; i++) { scanf(%d, &t); play(t); ret += remove(); } return ret; } int main () { int cas; scanf(%d, &cas); for (int kcas = 1; kcas <= cas; kcas++) { printf(Case %d: %d , kcas, solve ()); } return 0; } 
    
   
  

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