Can you solve this equation?
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 13292 Accepted Submission(s): 5937
Problem Description Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;
Now please try your lucky.
Input The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10);
Output For each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100.
Sample Input
2
100
-4
Sample Output
1.6152
No solution!
源代码（二分查找）
//1000
#include
#include
double f(double x) { return 8*pow(x,4)+7*pow(x,3)+2*pow(x,2)+3*x+6; } int main() { int t; double x1,x2,x3,y,y1,y2,y3; scanf(%d,&t); while(t--) { x1=0; x2=100; scanf(%lf,&y); y1=f(x1)-y; y2=f(x2)-y; if(y1>0||y2<0) printf(No solution! ); else { while(fabs(f(x1)-f(x2))>=0.00001) { x3=(x1+x2)/2; y3=f(x3)-y; if(y3>0) x2=x3; else x1=x3; y1=f(x1)-y; y2=f(x2)-y; } printf(%.4lf ,x3); } } return 0; }
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