E - Period
Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u
Submit Status
Description
For each prefix of a given string S with N characters (each character has an ASCII code between 97 and 126, inclusive), we want to know whether the prefix is a periodic string. That is, for each i (2 <= i <= N) we want to know the largest K > 1 (if there is one) such that the prefix of S with length i can be written as A K , that is A concatenated K times, for some string A. Of course, we also want to know the period K.
Input
The input file consists of several test cases. Each test case consists of two lines. The first one contains N (2 <= N <= 1 000 000) ? the size of the string S. The second line contains the string S. The input file ends with a line, having the number zero on it.
Output
For each test case, output “Test case #” and the consecutive test case number on a single line; then, for each prefix with length i that has a period K > 1, output the prefix size i and the period K separated by a single space; the prefix sizes must be in increasing order. Print a blank line after each test case.
Sample Input
3
aaa
12
aabaabaabaab
0
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t=i-next[i];表示已i结尾的前缀的循环节，关于kmp的next数组的性质，我前面的文章有介绍
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#include
#include
#include
#include
#include
//#include
using namespace std; template
inline T read(T&x) { char c; while((c=getchar())<=32)if(c==EOF)return 0; bool ok=false; if(c=='-')ok=true,c=getchar(); for(x=0; c>32; c=getchar()) x=x*10+c-'0'; if(ok)x=-x; return 1; } template
inline T read_(T&x,T&y) { return read(x)&&read(y); } template
inline T read__(T&x,T&y,T&z) { return read(x)&&read(y)&&read(z); } template
inline void write(T x) { if(x<0)putchar('-'),x=-x; if(x<10)putchar(x+'0'); else write(x/10),putchar(x%10+'0'); } template
inline void writeln(T x) { write(x); putchar('\n'); } //-------ZCC IO template------ const int maxn=1000001; const double inf=999999999; #define lson (rt<<1),L,M #define rson (rt<<1|1),M+1,R #define M ((L+R)>>1) #define For(i,t,n) for(int i=(t);i<(n);i++) typedef long long LL; typedef double DB; typedef pair
P; #define bug printf("---\n"); #define mod 1000000007 int nex[maxn]; char a[maxn]; void getnext(char*s) { int i=0,j=-1; nex[0]=-1; int len=strlen(s); while(i
1) { printf("%d %d\n",i,i/t); } } printf("\n"); } return 0; }
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