设为首页 加入收藏

TOP

poj3227
2014-11-23 19:09:18 来源: 作者: 【 】 浏览:5
Tags:poj3227
#include 
#include 
#include 

using namespace std;

#define eps 1e-8

struct point
{
    double x, y;
}p[1010];

double dist(point a, point b)
{
    return sqrt((a.x - b.x)*(a.x - b.x) + (a.y - b.y) * (a.y - b.y));
}

double get_K(point a, point b)
{
    return (b.y - a.y) * 1.0 / (b.x - a.x);
}

point intersection(point u1, point u2, point v1, point v2)
{
    point ret = u1;
    double t = ((u1.x - v1.x)*(v1.y - v2.y) - (u1.y - v1.y)*(v1.x - v2.x))
        / ((u1.x - u2.x)*(v1.y - v2.y) - (u1.y - u2.y)*(v1.x - v2.x));
    ret.x += (u2.x - u1.x)*t;
    ret.y += (u2.y - u1.y)*t;
    return ret;
}

int main()
{
    int n;
    double h;
    while (cin >> n >> h && (n || h))
    {
        p[0].x = 0, p[0].y = h;
        for (int i = 1; i <= n; i++)
        {
            cin >> p[i].x >> p[i].y;
        }
        double k = get_K(p[0], p[2]);
        double s = 1.0 * dist(p[1], p[2]);
        point mark = p[2];
        for (int i = 3; i <= n; i++)
        {
            
            if (get_K(p[0], p[i]) > k)
            {
                k = get_K(p[0], p[i]);
                point inter = intersection(p[0], mark, p[i], p[i - 1]);
                s += dist(p[i], inter);
                mark = p[i];
            }
        }
        cout < 
 

】【打印繁体】【投稿】【收藏】 【推荐】【举报】【评论】 【关闭】 【返回顶部
分享到: 
上一篇简单dfs hdu 4536 XCOM Enemy Unk.. 下一篇HDU 4305 Lightning (生成树的计..

评论

帐  号: 密码: (新用户注册)
验 证 码:
表  情:
内  容:

·求navicat for mysql (2025-12-26 13:21:33)
·有哪位大哥推荐一下m (2025-12-26 13:21:30)
·MySQL下载与安装教程 (2025-12-26 13:21:26)
·Linux_百度百科 (2025-12-26 12:51:52)
·Shell 流程控制 | 菜 (2025-12-26 12:51:49)