设为首页 加入收藏

TOP

uva 10106
2014-11-23 19:52:32 来源: 作者: 【 】 浏览:6
Tags:uva 10106

The Problem
The problem is to multiply two integers X, Y. (0<=X,Y<10250)

The Input
The input will consist of a set of pairs of lines. Each line in pair contains one multiplyer.

The Output
For each input pair of lines the output line should consist one integer the product.

Sample Input
12
12
2
222222222222222222222222
Sample Output
144
444444444444444444444444

#include 
#include 
#define MAXN 260
char str1[MAXN];
char str2[MAXN];
int s1[MAXN];
int s2[MAXN];
int s[MAXN * 2 + 10];

int main()
{
    int i,j,len1,len2;
    while(gets(str1) && gets(str2))
    {
        memset(s1,0,sizeof(s1));
        memset(s2,0,sizeof(s2));
        memset(s,0,sizeof(s));
        len1 = strlen(str1);
        len2 = strlen(str2);
        j = 0;
        for(i = len1 - 1; i >=0; i--)
        {
          s1[j++] = str1[i] - '0';
        }
        j = 0;
        for(i = len2 - 1; i >= 0; i--)
        {
            s2[j++] = str2[i] - '0';
        }

        for(i = 0; i < len2; i++)
        {
            for(j = 0; j < len1; j++)
            {
                s[i+j] += s2[i] * s1[j];
            }
        }
        for(i = 0; i < MAXN * 2 +2; i++)
        {
            if(s[i] >= 10)
            {
                s[i + 1] += s[i]/10;
                s[i] %= 10;
            }
        }
        int flag = 0;
        for(i = MAXN * 2 + 5; i >= 0; i--)
        {
            if(flag)
            {
                printf("%d", s[i]);
            }
            else if(s[i])
            {
                printf("%d", s[i]);
                flag = 1;
            }
        }
        if(!flag)
        {
            printf("0");
        }
        printf("\n");
    }
    return 0;
}

】【打印繁体】【投稿】【收藏】 【推荐】【举报】【评论】 【关闭】 【返回顶部
分享到: 
上一篇uva 10115 下一篇uva 424

评论

帐  号: 密码: (新用户注册)
验 证 码:
表  情:
内  容:

·C语言中,“指针”用 (2025-12-26 15:20:18)
·在c语言的指针运算中 (2025-12-26 15:20:15)
·C语言-函数指针与函 (2025-12-26 15:20:12)
·求navicat for mysql (2025-12-26 13:21:33)
·有哪位大哥推荐一下m (2025-12-26 13:21:30)