#include #include #include #include #include #include #include #include #include #include #include #include #include #include #define FF(i, a, b) for(int i=a; i=b; i--) #define REP(i, n) for(int i=0; i & P) const { return Cross(P[v[1]]-P[v[0]], P[v[2]]-P[v[0]]); } // f是否能看见P[i] int CanSee(const vector& P, int i) const { return Dot(P[i]-P[v[0]], Normal(P)) > 0; } }; // 增量法求三维凸包 // 注意:没有考虑各种特殊情况(如四点共面)。实践中,请在调用前对输入点进行微小扰动 vector CH3D(const vector& P) { int n = P.size(); vector > vis(n); for(int i = 0; i < n; i++) vis[i].resize(n); vector cur; cur.push_back(Face(0, 1, 2)); // 由于已经进行扰动,前三个点不共线 cur.push_back(Face(2, 1, 0)); for(int i = 3; i < n; i++) { vector next; // 计算每条边的“左面”的可见性 for(int j = 0; j < cur.size(); j++) { Face& f = cur[j]; int res = f.CanSee(P, i); if(!res) next.push_back(f); for(int k = 0; k < 3; k++) vis[f.v[k]][f.v[(k+1)%3]] = res; } for(int j = 0; j < cur.size(); j++) for(int k = 0; k < 3; k++) { int a = cur[j].v[k], b = cur[j].v[(k+1)%3]; if(vis[a][b] != vis[b][a] && vis[a][b]) // (a,b)是分界线,左边对P[i]可见 next.push_back(Face(a, b, i)); } cur = next; } return cur; } struct ConvexPolyhedron { int n; vector P, P2; vector faces; bool read() { if(scanf("%d", &n) != 1) return false; P.resize(n); P2.resize(n); for(int i = 0; i < n; i++) { P[i] = read_point3(); P2[i] = add_noise(P[i]); } faces = CH3D(P2); return true; } Point3 centroid() { Point3 C = P[0]; double totv = 0; Point3 tot(0,0,0); for(int i = 0; i < faces.size(); i++) { Point3 p1 = P[faces[i].v[0]], p2 = P[faces[i].v[1]], p3 = P[faces[i].v[2]]; double v = -Volume6(p1, p2, p3, C); totv += v; tot = tot + Centroid(p1, p2, p3, C)*v; } return tot / totv; } double mindist(Point3 C) { double ans = 1e30; for(int i = 0; i < faces.size(); i++) { Point3 p1 = P[faces[i].v[0]], p2 = P[faces[i].v[1]], p3 = P[faces[i].v[2]]; ans = min(ans, fabs(-Volume6(p1, p2, p3, C) / Area2(p1, p2, p3))); } return ans; } }P1; int main() { int n, m; ConvexPolyhedron P1, P2; while(P1.read()) { Point3 C1 = P1.centroid(); double d1 = P1.mindist(C1); printf("%.3f\n", d1); } return 0; }