'A' -> 1
'B' -> 2
...
'Z' -> 26
Given an encoded message containing digits, determine the total number of ways to decode it.
For example,
Given encoded message "12", it could be decoded as "AB" (1 2) or "L" (12).
The number of ways decoding "12" is 2.
dp:
int numDecodings(string s) {
// Start typing your C/
C++ solution below
// DO NOT write int main() function
int length = s.size();
if(length<1)return 0;
int* dp = new int[length+1];
memset(dp, 0, sizeof(int)*(length+1));
dp[0] = 1;
if(s[0] == '0')dp[1] = 0;
else dp[1] = 1;
for(int i = 2; i <= length; ++i)
{
int num = stoi(s.substr(i-1,1));
if(num > 0)
dp[i] = dp[i-1];
num = stoi(s.substr(i-2,2));
if(num > 9 && num < 27)
dp[i] += dp[i-2];
}
int res = dp[length];
delete[] dp;
return res;
}