Description
You are given a string consisting of parentheses () and []. A string of this type is said to be correct:
(a)
if it is the empty string
(b)
if A and B are correct, AB is correct,
(c)
if A is correct, (A) and [A] is correct.
Write a program that takes a sequence of strings of this type and check their correctness. Your program can assume that the maximum string length is 128.
Input
The file contains a positive integer n and a sequence of n strings of parentheses () and [], one string a line.
Output
A sequence of Yes or No on the output file.
Sample Input
3
([])
(([()])))
([()[]()])()
Sample Output
Yes
No
Yes
这个题的意思是看一个表达示的括号是不是平衡的,空表达示也是平衡的,平衡就输出YES,否则输出NO。
解题思路:
1.如果表达示为空,输出YES。
2.利用一个栈,表达示从左到右扫描,遇到左括号入栈,右括号出栈,如果最后线空输出YES,否则输出NO。
include#include #include #include #include #include using namespace std; char f(char c) { if(c==')')return '('; if(c==']')return '['; return 0; } bool judge(const string& s) { stack st; st.push('0'); for(int i=0;i >n; string s; getchar(); while(n--) { getline(cin,s); if(s.size()==0||judge(s))cout<<"Yes"<