解数独算法--C++实现

2014-11-24 00:12:13 · 作者: · 浏览: 5
  #include 
using namespace std;
//可选数字
int candidate[] = {1,2,3,4,5,6,7,8,9};
//标记这个空格是否为原始数据
int g_a[9][9] = {0};
//打印函数
void print( int (*a)[9] )
{
for( int i = 0; i < 9; i++ )
{
  for( int j = 0; j < 9; j++ )
  {
   cout << a[i][j] << " ";
  }
  cout << endl;
}
cout << endl;
}
//判断可以放哪些数字
void ConfirmCandidate( int (*a)[9], int i, int j )
{
for( int i_candidate = 0; i_candidate < 9; i_candidate++ )
  candidate[i_candidate] = i_candidate+1;
for( int colm = 0; colm < 9; colm++ )
{
  if( a[i][colm] != 0 )
   candidate[a[i][colm]-1] = 0;
}
for( int line = 0; line < 9; line++ )
{
  if( a[line][j] != 0 )
   candidate[a[line][j]-1] = 0;
}
for( int line = i/3*3; line < i/3*3+3; line++ )
{
  for( int colm = j/3*3; colm < j/3*3+3; colm++ )
   if( a[line][colm] != 0 )
    candidate[a[line][colm]-1] = 0;
}
}
//标记每个空格位置
void TotalNumbers( int (*a)[9], int i, int j )
{
for( int line = 0; line < i; line++ )
{
  for( int colm = 0; colm < j; colm++ )
   if( a[line][colm] == 0 )
   {
    g_a[line][colm] = 1;
   }
}
}
//判断所填数字是否正确
bool Judgeva lue( int (*a)[9],int i, int j )
{
//同一行有无重复数字
for( int colm = 0; colm < 9; colm++ )
{
  if( a[i][colm] == a[i][j] && j != colm )
   return false;
}
//同一列有无重复数字
for( int line = 0; line < 9; line++ )
{
  if( a[line][j] == a[i][j] && i != line )
   return false;
}
//一个3*3的方格内有无重复数字
for( int line = i/3*3; line < i/3*3+3; line++ )
{
  for( int colm = j/3*3; colm < j/3*3+3; colm++ )
   if( a[line][colm] == a[i][j] && i != line && j != colm )
    return false;
}
return true;
}
//判断是否成功
bool success( int(*a)[9], int i, int j )
{
if( i < 0 || j < 0 ) return false;
int line = i;
int colm = j;
for( ; line < 9; line++, colm = 0 )
{
  for( ; colm < 9; colm++ )
  {
   //cout << "line = " << line <<"  colm = " << colm << endl;
   //if( colm == 8 && line == 8 ) return true;
   if( a[line][colm] != 0 && g_a[line][colm] == 0 ) continue;
   ConfirmCandidate(a, line, colm);
   for(int c = 0; c < 9; c++ )
   {
    if( candidate[c] >
a[line][colm] ) { a[line][colm] = candidate[c]; /* *TEST *测试可选数字 */ /* for(int i = 0; i < 9; i++ ) cout << candidate[i] << " "; cout << endl << endl; */ //print(a); //判断放入的值是否正确 bool bRet = Judgeva lue( a, line, colm ); if(!bRet) { //cout << "bRet is false" << endl; } else{ //cout << "bRet is true" << endl; break; } } else if( c == 8 && candidate[c] <= a[line][colm] ) { //cout << "line = " << line <<" colm = " << colm << endl; int set_colm = 8; a[line][colm] = 0; if( colm == 0 ) { while( g_a[line-1][set_colm] == 0) { if( set_colm == 0) { line--; set_colm = 8; } else set_colm--; } return success( a, line - 1, set_colm); } else{ while( g_a[line][colm-1] == 0) { if( set_colm == 0) { line--; set_colm = 8; } else colm--; } return success( a ,line, colm-1 ); } } } } } return true; } http://www.shengshiyouxi.com int main() { //initialization int a[9][9] = { {8,0,0,0,0,0,0,0,0}, {0,0,3,6,0,0,0,0,0}, {0,7,0,0,9,0,2,0,0}, {0,5,0,0,0,7,0,0,0}, {0,0,0,0,4,5,7,0,0}, {0,0,7,1,0,0,0,3,0}, {0,0,1,0,0,0,0,6,8}, {0,0,8,5,0,0,0,1,0}, {0,9,0,0,0,0,4,0,0} }; //test /* int a[9][9] = { {8,0,0,0,0,0,0,0,0}, {0,0,0,0,0,0,0,0,0}, {0,0,0,0,0,0,0,0,0}, {0,0,0,0,0,0,0,0,0}, {0,0,0,0,0,0,0,0,0}, {0,0,0,0,0,0,0,0,0}, {0,0,0,0,0,0,0,6,8}, {0,0,0,0,0,0,0,0,0}, {0,0,0,0,0,0,0,0,0} }; */ TotalNumbers( a, 9, 9 ); success( a, 0, 0 ); print(a); }