Given any positive integer N, you are supposed to find all of its prime factors, and write them in the format N = p1^k1 * p2^k2 *…*pm^km.
Input Specification:
Each input file contains one test case which gives a positive integer N in the range of long int.
Output Specification:
Factor N in the format N = p1^k1 * p2^k2 *…*pm^km, where pi's are prime factors of N in increasing order, and the exponent ki is the number of pi -- hence when there is only one pi, ki is 1 and must NOT be printed out.
Sample Input:
97532468
Sample Output:
97532468=2^2*11*17*101*1291
分析:(1)先建立素数组(2)要考虑输入为 1 的特例。
参考代码:
#include#include using namespace std; #define max 1000 int prime[max]; int i; int j; bool isPrime(int temp) { int t; bool flag = true; for(t = 2; t <= sqrt(temp); t++) if( temp%t == 0) {flag = false; break;} return flag; } int main() { prime[0] = 2; j = 3; for(i=1; i >input; cout<= 1) { cout<1) cout<<"^"<