poj 2472

2014-11-24 02:27:52 · 作者: · 浏览: 2

[cpp]
//卧槽这种水题WA的泪流满面
//floyd的中转点要放在最上层循环比较好

#include
#include
#include
using namespace std;
#define MAXN 110

int n,m;


double dist[MAXN][MAXN];

int a,b,p;


void Floyd()
{
for(int k = 1; k <= n; k++)
for(int i = 1; i <= n; i++)
{
for(int j = 1; j <= n; j++)
{
if(dist[i][j] < dist[i][k]*dist[k][j])
dist[i][j] = dist[i][k]*dist[k][j];
}
}
}

int main()
{
while(scanf("%d",&n)!=EOF &&n)
{
if(n == 0)
break;
cin>>m;
for(int i = 1; i <= n; i++)
{
for(int j = 1; j <= n; j++)
{
if(i == j)
dist[i][j] = 1;
else
dist[i][j] = 0;
}
}
// while(m--)
for(int i = 0; i < m; i++)
{
cin>>a>>b>>p;
dist[a][b] = dist[b][a] =(double)p/100;

}
Floyd();
printf("%.6lf percent\n",dist[1][n]*100);

}

return 0;

}

//卧槽这种水题WA的泪流满面
//floyd的中转点要放在最上层循环比较好

#include
#include
#include
using namespace std;
#define MAXN 110

int n,m;


double dist[MAXN][MAXN];

int a,b,p;


void Floyd()
{
for(int k = 1; k <= n; k++)
for(int i = 1; i <= n; i++)
{
for(int j = 1; j <= n; j++)
{
if(dist[i][j] < dist[i][k]*dist[k][j])
dist[i][j] = dist[i][k]*dist[k][j];
}
}
}

int main()
{
while(scanf("%d",&n)!=EOF &&n)
{
if(n == 0)
break;
cin>>m;
for(int i = 1; i <= n; i++)
{
for(int j = 1; j <= n; j++)
{
if(i == j)
dist[i][j] = 1;
else
dist[i][j] = 0;
}
}
// while(m--)
for(int i = 0; i < m; i++)
{
cin>>a>>b>>p;
dist[a][b] = dist[b][a] =(double)p/100;

}
Floyd();
printf("%.6lf percent\n",dist[1][n]*100);

}

return 0;

}