Trapping Rain Water
Total Accepted: 2335 Total Submissions: 8464My SubmissionsGiven n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining.
For example,
Given [0,1,0,2,1,0,1,3,2,1,2,1], return 6.

The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of rain water (blue section) are being trapped. Thanks Marcos fZ http://www.2cto.com/kf/ware/vc/" target="_blank" class="keylink">vciBjb250cmlidXRpbmcKIHRoaXMgaW1hZ2UhPC9wPgo8cD48L3A+CgoKCgoKPHA+PC9wPgo8cCBjbGFzcz0="action"> Discuss
Find the highest, then from the start to the highest, then the last to the highest..
class Solution {
public:
int trap(int A[], int n) {
if (n <= 2)
return 0;
int i, maxElevation = A[0], maxIndex = 0, h = 0, res = 0;
for (i = 1; i < n; ++i)
if (A[i] > maxElevation) {
maxElevation = A[i];
maxIndex = i;
}
for (i = 0; i <= maxIndex - 1; ++i)
if (A[i] >= h)
h = A[i];
else
res += (h - A[i]);
h = 0;
for (i = n - 1; i >= maxIndex + 1; --i)
if (A[i] >= h)
h = A[i];
else
res += (h - A[i]);
return res;
}
};