题目链接：fzu 1909 An Equation
典型的签到题。
#include#include bool judge(int *a, int sum) { for (int i = 0; i < 4; i++) { for (int j = i + 1; j < 4; j++) if (sum == (a[i] + a[j]) * 2) return true; } return false; } int main () { int cas, a[4]; scanf("%d", &cas); for (int i = 1; i <= cas; i++) { int sum = 0; for (int j = 0; j < 4; j++) { scanf("%d", &a[j]); sum += a[j]; } printf("Case %d: %s\n", i, judge(a, sum) "Yes" : "No"); } return 0; }