杭电1049

2014-11-24 07:35:54 · 作者: · 浏览: 3
#include
int main (void)
{
int n,u,d,i,s;
while(scanf("%d%d%d",&n,&u,&d)!=EOF&&n)
{
s=0;
if((n-u)%(u-d)==0)
printf("%d\n",(n-u)/(u-d)*2+1);
else
if(n-(n-u)/(u-d)*(u-d)>u)
printf("%d\n",((n-u)/(u-d))*2+3);
else
if(n-(n-u)/(u-d)*(u-d)==u)
printf("%d\n",((n-u)/(u-d))*2+1);
}
return 0;
}