顺手写个单调队列。。。。
Bad Hair Day
[Submit] [Go Back] [Status] Description Some of Farmer John's N cows (1 ≤ N ≤ 80,000) are having a bad hair day! Since each cow is self-conscious about her messy hairstyle, FJ wants to count the number of other cows that can see the top of other cows' heads. Each cow i has a specified height hi (1 ≤ hi ≤ 1,000,000,000) and is standing in a line of cows all facing east (to the right in our diagrams). Therefore, cow i can see the tops of the heads of cows in front of her (namely cows i+1, i+2, and so on), for as long as these cows are strictly shorter than cow i. Consider this example: = = = = - = Cows facing right --> = = = = - = = = = = = = = = 1 2 3 4 5 6 Cow#1 can see the hairstyle of cows #2, 3, 4 Let ci denote the number of cows whose hairstyle is visible from cow i; please compute the sum of c1 through cN.For this example, the desired is answer 3 + 0 + 1 + 0 + 1 + 0 = 5. Input Line 1: The number of cows, N.Lines 2..N+1: Line i+1 contains a single integer that is the height of cow i. Output Sample Input 6 10 3 7 4 12 2 Sample Output 5 Source USACO 2006 November Silver[Submit] [Go Back] [Status] |
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#include#include #include #include #include #include using namespace std; long long int n,ct[88888]; struct node { long long int h,id; }H[88888]; stack q; int main() { scanf("%I64d",&n); for(int i=0;i =0;i--) { while(!q.empty()&&q.top().h
