中介者模式----C++实现

2014-11-24 08:06:31 · 作者: · 浏览: 0

中介者模式

定义:

用一个中介对象来封装一系列的对象交互。中介者使对象不需要显示的相互引用,从而使其耦合松散,而且可以独立的完成改变它们之间的交互。

适用性:

1、 一组对象以定义良好但是复杂的方式进行通信。产生的相互依赖关系结构混乱且难以理解。

2、 一个对象引用其他很多对象并且直接与这些对象通信,导致难以复用该对象。

3、 想定制一个分布在多个类中的行为,而又不想生成太多的子类。

优点:

1、 减少了子类的生成

2、 将colleague类解耦

3、 简化了对象协议

4、 对对象如何协作进行了抽象。

缺点:

控制集中化,使得中介者变得复杂而难以维护。

结构:

\

实现:< http://www.2cto.com/kf/ware/vc/" target="_blank" class="keylink">vcD4KPHAgYWxpZ249"left">class Mediator;

class Colleague

{

public:

Colleague(string name,Mediator*pMediator):m_name(name),m_pMediator(pMediator)

{}

virtual void SendMessage(string mes) {}

virtual void ReceiveMessage(string mes) {}

string GetName()

{

returnm_name;

}

protected:

string m_name;

Mediator *m_pMediator;

};

class Mediator

{

public:

virtual~Mediator() {}

virtual void SetColleagueA(Colleague *pa)

{ }

virtual void SetColleagueB(Colleague *pb)

{ }

virtual void TransmitMessage(string mes, Colleague *p)

{ }

};

class ConcreteMediator:public Mediator

{

public:

void SetColleagueA(Colleague *pa)

{

m_pColleagueA = pa;

}

void SetColleagueB(Colleague *pb)

{

m_pColleagueB = pb;

}

void TransmitMessage(string mes, Colleague *p)

{

mes = p->GetName() + "\n\r message: " + mes ;

if (p ==m_pColleagueA)

{

m_pColleagueB->ReceiveMessage(mes);

}

else if(p == m_pColleagueB)

{

m_pColleagueA->ReceiveMessage(mes);

}

}

private:

Colleague *m_pColleagueA;

Colleague *m_pColleagueB;

};

class ConcreteColleagueA:public Colleague

{

public:

ConcreteColleagueA(string name,Mediator*pMediator):Colleague(name,pMediator)

{}

void SendMessage(string mes)

{

m_pMediator->TransmitMessage(mes,this);

}

void ReceiveMessage(string mes)

{

cout<

}

};

class ConcreteColleagueB:public Colleague

{

public:

ConcreteColleagueB(string name,Mediator*pMediator):Colleague(name,pMediator)

{}

void SendMessage(string mes)

{

m_pMediator->TransmitMessage(mes,this);

}

void ReceiveMessage(string mes)

{

cout<

}

};

Mediator *pm = newConcreteMediator();

Colleague *pa = newConcreteColleagueA("colleagueA",pm);

Colleague *pb = newConcreteColleagueB("colleagueB",pm);

pm->SetColleagueA(pa);

pm->SetColleagueB(pb);

pa->SendMessage("hello ,my name is lily");

pb->SendMessage("hello lily ,my name is liming");