John
Time Limit: 5000/1000 MS (Java/Others) Memory Limit: 65535/32768 K (Java/Others)Total Submission(s): 2412 Accepted Submission(s): 1303
Problem Description Little John is playing very funny game with his younger brother. There is one big box filled with M&Ms of different colors. At first John has to eat several M&Ms of the same color. Then his opponent has to make a turn. And so on. Please note that each player has to eat at least one M&M during his turn. If John (or his brother) will eat the last M&M from the box he will be considered as a looser and he will have to buy a new candy box.
Both of players are using optimal game strategy. John starts first always. You will be given information about M&Ms and your task is to determine a winner of such a beautiful game.
Input The first line of input will contain a single integer T the number of test cases. Next T pairs of lines will describe tests in a following format. The first line of each test will contain an integer N the amount of different M&M colors in a box. Next line will contain N integers Ai, separated by spaces amount of M&Ms of i-th color.
Constraints:
1 <= T <= 474,
1 <= N <= 47,
1 <= Ai <= 4747
Output Output T lines each of them containing information about game winner. Print “John” if John will win the game or “Brother” in other case.
Sample Input
2 3 3 5 1 1 1
Sample Output
John Brother
Source Southeastern Europe 2007
当每一堆都为1时,即都是孤单堆时,需要特殊考虑。
否则对每一项抑或,假如等于0,则后手胜,否则先手胜。
代码:
/* *********************************************** Author :xianxingwuguan Created Time :2014-2-8 0:11:46 File Name :1.cpp ************************************************ */ #pragma comment(linker, "/STACK:102400000,102400000") #include#include #include #include #include #include #include #include #include #include #include #include #include #include