UVa 621 秘密研究

2014-11-24 08:55:43 · 作者: · 浏览: 0

/*

* 解题思路:

* 很简单的一道水题,直接按题目讯息输出即可

*/

#include 
  
   
#include 
   
     int main( ) { int t; int len; char s[ 1000 ]; scanf("%d",&t); while( t-- ) { scanf("%s",s); len = strlen( s ); if( (s[ 0 ] == '1' && len == 1) || (s[ 0 ] == '4' && len == 1 ) || ( s[ 0 ] == '7' && s[ 1 ] == '8' && len == 2 ) ) printf("+\n"); else if( s[ len-1 ] == '5' && s[ len-2 ] == '3' ) printf("-\n"); else if( s[ 0 ] == '9' && s[ len-1 ] == '4' ) printf("*\n"); else if( s[ 0 ] == '1' && s[ 1 ] == '9' && s[ 2 ] == '0' ) printf(" \n"); } return 0; }