“Oh, God! How terrible! ”
Don’t be so afraid, guys. Although he hides in a cave of Hang Zhou, he dares not to go out. Laden is so bored recent years that he fling himself into some math problems, and he said that if anyone can solve his problem, he will give himself up!
Ha-ha! Obviously, Laden is too proud of his intelligence! But, what is his problem
“Given some Chinese Coins (硬币) (three kinds-- 1, 2, 5), and their number is num_1, num_2 and num_5 respectively, please output the minimum value that you cannot pay with given coins.”
You, super ACMer, should solve the problem easily, and don’t fZ http://www.2cto.com/kf/ware/vc/" target="_blank" class="keylink">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"brush:java;">1 1 3 0 0 0
Sample Output
4
构造母函数解决：
#include#include #include using namespace std; #include int a[10005],b[10005]; int num[4]; int main() { freopen("C:\\in.txt","r",stdin); while(scanf("%d %d %d",&num[1],&num[2],&num[3])!=EOF){ int v[4]={0,1,2,5}; if(!num[1]&&!num[2]&&!num[3])break; int sum=0; for(int i=1;i<=3;i++) sum+=num[i]*v[i]; memset(a,0,sizeof(a)); memset(b,0,sizeof(b)); a[0]=1; for(int i=1;i<=3;i++){ for(int j=0;j<=sum;j++) if(a[j]) for(int k=0;k*v[i]+j<=sum&&k<=num[i];k++) b[k*v[i]+j]+=a[j]; for(int j=0;j<=sum;j++) { a[j]=b[j]; b[j]=0; } } int index=0; for(int i=0;i<=10000;i++){ if(!a[i]){ index=i; break; } } printf("%d\n",index); } return 0; }