题目
Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum.
For example:Given the below binary tree and
sum = 22,
5
/ \
4 8
/ / \
11 13 4
/ \ / \
7 2 5 1
return
[ [5,4,11,2], [5,8,4,5] ]分析
这题直接用递归写,类似DFS。
代码
import java.util.ArrayList;
public class PathSumII {
public class TreeNode {
int val;
TreeNode left;
TreeNode right;
TreeNode(int x) {
val = x;
}
}
private ArrayList
> results;
public ArrayList
> pathSum(TreeNode root, int sum) { results = new ArrayList
>(); ArrayList
list = new ArrayList
(); solve(root, sum, list); return results; } private void solve(TreeNode root, int sum, ArrayList
list) { if (root == null) { return; } list.add(root.val); if (sum == root.val && root.left == null && root.right == null) { results.add(new ArrayList
(list)); } else { solve(root.left, sum - root.val, list); solve(root.right, sum - root.val, list); } list.remove(list.size() - 1); } }