LeetCode | Wildcard Matching

2014-11-24 11:28:59 · 作者: · 浏览: 0

题目

Implement wildcard pattern matching with support for ' ' and '*'.

' ' Matches any single character.
'*' Matches any sequence of characters (including the empty sequence).

The matching should cover the entire input string (not partial).

The function prototype should be:
bool isMatch(const char *s, const char *p)

Some examples:
isMatch("aa","a") → false
isMatch("aa","aa") → true
isMatch("aaa","aa") → false
isMatch("aa", "*") → true
isMatch("aa", "a*") → true
isMatch("ab", " *") → true
isMatch("aab", "c*a*b") → false
分析

通过率很低的一题,Java没指针写起来是不顺畅。

贪心的策略,能匹配就一直往后遍历,匹配不上了就看看前面有没有'*'来救救场,再从'*'后面接着试。

代码

public class WildcardMatching {
	public boolean isMatch(String s, String p) {
		int i = 0;
		int j = 0;
		int star = -1;
		int mark = -1;
		while (i < s.length()) {
			if (j < p.length()
					&& (p.charAt(j) == ' ' || p.charAt(j) == s.charAt(i))) {
				++i;
				++j;
			} else if (j < p.length() && p.charAt(j) == '*') {
				star = j++;
				mark = i;
			} else if (star != -1) {
				j = star + 1;
				i = ++mark;
			} else {
				return false;
			}
		}
		while (j < p.length() && p.charAt(j) == '*') {
			++j;
		}
		return j == p.length();
	}
}