To make the birthday cake look more beautiful, Ran and Chen decide to place them like r ≥ 1 concentric circles. They place k i candles equidistantly on the i-th circle, where k ≥ 2, 1 ≤ i ≤ r. And it's optional to place at most one candle at the center of the cake. In case that there are a lot of different pairs of r and k satisfying these restrictions, they want to minimize r × k. If there is still a tie, minimize r.
Input There are about 10,000 test cases. Process to the end of file.
Each test consists of only an integer 18 ≤ n ≤ 10 12.
Output For each test case, output r and k.
Sample Input
18 111 1111
1 17 2 10 3 10
题意: 将蛋糕分作r个同心圆,圆心可以放一个或者不放蜡烛,然后同心圆从内到外,第i个同心圆放k^i个蜡烛,问r*k最小的时候,r,k的值分别是多少,r*k相同时,输出r最小的
思路: 首先用等比数列求和公式估测出r最大的值为40左右,那么枚举r,并对k进行二分匹配答案即可
#include#include #include #include using namespace std; #define ll __int64 ll n; ll bin(ll s) { ll l = 2,r = n,mid,i; while(l<=r) { mid = (l+r)/2; ll sum = 1,ans = 0;; for(i = 1; i<=s; i++) { if(n/sum n)//放置溢出 break; } if(ans == n || ans == n-1) return mid; else if(ans