Number Sequence(杭电1711)(KMP)

2015-01-27 05:56:40 · 作者: · 浏览: 6

Number Sequence

Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 11925 Accepted Submission(s): 5440


Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which make a[K] = b[1], a[K + 1] = b[2], ...... , a[K + M - 1] = b[M]. If there are more than one K exist, output the smallest one.

Input The first line of input is a number T which indicate the number of cases. Each case contains three lines. The first line is two numbers N and M (1 <= M <= 10000, 1 <= N <= 1000000). The second line contains N integers which indicate a[1], a[2], ...... , a[N]. The third line contains M integers which indicate b[1], b[2], ...... , b[M]. All integers are in the range of [-1000000, 1000000].

Output For each test case, you should output one line which only contain K described above. If no such K exists, output -1 instead.

Sample Input
2
13 5
1 2 1 2 3 1 2 3 1 3 2 1 2
1 2 3 1 3
13 5
1 2 1 2 3 1 2 3 1 3 2 1 2
1 2 3 2 1

Sample Output
6
-1

Source HDU 2007-Spring Programming Contest
/*KMP算法关键是求next函数,第一道KMP题,最基础的题,
借鉴普浩冉的代码和讲解,还算有点理解吧= = 
*/
#include
  
   
int a[1000002];
int s[10002],next[10002];
int m,n;
void get_next(int *s)
{
	int i=0,j=-1;
	next[0]=-1;
	while(i