Description
Somewhere deep in the Czech Technical University buildings, there are laboratories for examining mechanical and electrical properties of various materials. In one of yesterday’s presentations, you have seen how was one of the laboratories changed into a new multimedia lab. But there are still others, serving to their original purposes.In this task, you are to write software for a robot that handles samples in such a laboratory. Imagine there are material samples lined up on a running belt. The samples have different heights, which may cause troubles to the next processing unit. To eliminate such troubles, we need to sort the samples by their height into the ascending order.
Reordering is done by a mechanical robot arm, which is able to pick up any number of consecutive samples and turn them round, such that their mutual order is reversed. In other words, one robot operation can reverse the order of samples on positions between A and B.
A possible way to sort the samples is to find the position of the smallest one (P1) and reverse the order between positions 1 and P1, which causes the smallest sample to become first. Then we find the second one on position P and reverse the order between 2 and P2. Then the third sample is located etc.
The picture shows a simple example of 6 samples. The smallest one is on the 4th pZ??http://www.2cto.com/kf/ware/vc/" target="_blank" class="keylink">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"pst"> Input The input consists of several scenarios. Each scenario is described by two lines. The first line contains one integer number N , the number of samples, 1 ≤ N ≤ 100 000. The second line lists exactly N space-separated positive integers, they specify the heights of individual samples and their initial order.
The last scenario is followed by a line containing zero.
Output
Each Pi must be an integer (1 ≤ Pi ≤ N ) giving the position of the i-th sample just before the i-th reversal operation.
Note that if a sample is already on its correct position Pi , you should output the number Pi anyway, indicating that the “interval between Pi and Pi ” (a single sample) should be reversed.
Sample Input
6 3 4 5 1 6 2 4 3 3 2 1 0
Sample Output
4 6 4 5 6 6 4 2 4 4
用翻转对区间排序，建一个splay为1,2，...n，搞一个结构体数组A[maxn]，first保存key，second保存在初始数组中的下标，按照key排个序，则A[i].second就是第i大的元素在splay中的编号，每次将其旋转到跟，比他小的元素加上i就是此时他在元素中的位置，输出后删除树根(因为这一