Interval（南阳oj522）（树状数组）

Interval

描述

There are n(1 <= n <= 100000) intervals [ai, bi] and m(1 <= m <= 100000) queries, -100000 <= ai <= bi <= 100000 are integers. Each query contains an integer xi(-100000 <= x <= 100000). For each query, you should answer how many intervals convers xi.

输入

The first line of input is the number of test case.
For each test case,
two integers n m on the first line,
then n lines, each line contains two integers ai, bi;

then m lines, each line contains an integer xi.

输出

m lines, each line an integer, the number of intervals that covers xi.

样例输入

2
3 4
1 3
1 2
2 3
0
1
2
3
1 3
0 0
-1
0
1

样例输出

0
2
3
2
0
1
0

/*树状数组应用，统计数字在所给区间出现的次数。
TLE哭了，MAX大小：200002是AC，200005是TLE！！！
注意将负数转换到正值区间上，否则还是会TLE！！！ 
*/
#include
       
        
#include
        
          #define MAX 200002 int a[MAX]; int lowbit(int N) { return N&(-N); } void asd(int i,int M) { while(i<=MAX) { a[i]+=M; i+=lowbit(i); } } int sum(int j) { int sum=0; while(j>0) { sum+=a[j]; j-=lowbit(j); } return sum; } int main() { int i,n,m,T,t,k,p; scanf("%d",&T); while(T--) { memset(a,0,sizeof(a)); scanf("%d%d",&m,&n); while(m--) { scanf("%d%d",&k,&t); asd(k+100001,1); asd(t+100002,-1); } while(n--) { scanf("%d",&p); printf("%d\n",sum(p+100001)); } } return 0; }
        
       

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