HDU 3079 Vowel Counting (水)

2015-01-27 06:24:59 · 作者: · 浏览: 8

Vowel Counting

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1413 Accepted Submission(s): 1043


Problem Description The "Vowel-Counting-Word"(VCW), complies with the following conditions.
Each vowel in the word must be uppercase.
Each consonant (the letters except the vowels) must be lowercase.
For example, "ApplE" is the VCW of "aPPle", "jUhUA" is the VCW of "Juhua".
Give you some words; your task is to get the "Vowel-Counting-Word" of each word.

Input The first line of the input contains an integer T (T<=20) which means the number of test cases.
For each case, there is a line contains the word (only contains uppercase and lowercase). The length of the word is not greater than 50.

Output For each case, output its Vowel-Counting-Word.
Sample Input
4
XYz
application
qwcvb
aeioOa 

Sample Output
xyz
ApplIcAtIOn
qwcvb
AEIOOA





解题思路:水题一枚,字符大小写转化问题。






AC代码:

#include 
  
   
#include 
   
     #include 
    
      using namespace std; int main(){ // freopen("in.txt", "r", stdin); int t; string s; while(scanf("%d", &t)!=EOF){ cin>>s; for(int i=0; i
     
      ='a' && s[i]<='z') s[i] -= 32; printf("%c", s[i]); } else{ if(s[i]>='A' && s[i]<='Z') s[i] += 32; printf("%c", s[i]); } } printf("\n"); } return 0; }