Charm Bracelet（poj3624）（01背包）

Description

Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (1 ≤ N ≤ 3,402) available charms. Each charm i in the supplied list has a weightW_i (1 ≤ W_i ≤ 400), a 'desirability' factor D_i (1 ≤ D_i ≤ 100), and can be used at most once. Bessie can only support a charm bracelet whose weight is no more than M (1 ≤ M ≤ 12,880).

Given that weight limit as a constraint and a list of the charms with their weights and desirability rating, deduce the maximum possible sum of ratings.

Input

* Line 1: Two space-separated integers: N and M
* Lines 2..N+1: Line i+1 describes charm i with two space-separated integers: W_i and D_i

Output

* Line 1: A single integer that is the greatest sum of charm desirabilities that can be achieved given the weight constraints

Sample Input

4 6
1 4
2 6
3 12
2 7

Sample Output

23

#include
   
    
#include
    
      #include
     
       using namespace std; int main() { int i,j,n,m; int a[3500],b[3500],dp[13000]; while(scanf("%d %d",&n,&m)!=EOF) { for(i=1;i<=n;i++) { scanf("%d %d",&a[i],&b[i]); } memset(dp,0,sizeof(dp)); for(i=1;i<=n;i++) { for(j=m;j>=a[i];j--) dp[j]=max(dp[j],dp[j-a[i]]+b[i]); } printf("%d\n",dp[m]); } return 0; }