A + B

Time Limit: 2000/1000 MS ( Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 12192 Accepted Submission(s): 7132

Problem Description 读入两个小于100的正整数A和B,计算A+B.
需要注意的是:A和B的每一位数字由对应的英文单词给出.

Input 测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出.

Output 对每个测试用例输出1行,即A+B的值.

Sample Input

one + two =
three four + five six =
zero seven + eight nine =
zero + zero =

Sample Output

3
90
96

Source 浙大计算机研究生复试上机考试-2005年

#include 
  
   
#include 
   
     #define maxn 100 const char *sam[] = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"}; char buf[maxn]; int calVal(char str[]) { for(int i = 0; i < 10; ++i) if(!strcmp(buf, sam[i])) return i; } int main() { int mode = 0, a[2]; a[0] = a[1] = 0; while(scanf("%s", buf) == 1) { if(!strcmp(buf, "+")) { ++mode; continue; } else if(!strcmp(buf, "=")) { if(a[0] + a[1] == 0) break; printf("%d\n", a[0] + a[1]); mode = a[0] = a[1] = 0; continue; } a[mode] = a[mode] * 10 + calVal(buf); } return 0; }

HDU1223 A + B

A + B