题目链接：hdu 5077 NAND
题目大意：Xiaoqiang要写一个编码程序，然后根据x1，x2，x3的值构造出8个字符，现在给定要求生成的8个字符，问
说Xiaoqiang最少要写多少行代码。代码内容只能为NAND操作和return操作，操作的变量可以是常数。
解题思路：输入总共就256中情况，所以暴力剪枝打表，打表的代码手贱给删了。。。所以就将一下思路，开一个s数组
表示变量，然后对应每一层每次两个变量进行NAND操作。
大致三个剪枝，dfs时候，变量出现相同就跳过；8个字符可以直接根据数的位运算计算；单前层出现相同的跳过。
#include
#include
#include
using namespace std; const int ans[300] = {1, 5, 6, 3, 6, 3, 7, 4, 7, 8, 4, 5, 4, 5, 4, 1, 6, 3, 7, 4, 7, 4, 9, 7, 8, 8, 7, 5, 7, 5, 7, 4, 7, 8, 4, 5, 8, 8, 7, 5, 8, 9, 5, 6, 8, 8, 5, 5, 4, 5, 4, 1, 7, 5, 7, 4, 8, 8, 5, 5, 5, 7, 6, 4, 7, 8, 8, 8, 4, 5, 7, 5, 8, 9, 8, 8, 5, 6, 5, 5, 4, 5, 7, 5, 4, 1, 7, 4, 8, 8, 5, 7, 5, 5, 6, 4, 8, 9, 8, 8, 8, 8, 5, 7, 11, 9, 8, 9, 8, 9, 8, 8, 5, 6, 5, 5, 5, 5, 6, 4, 8, 9, 8, 8, 8, 8, 8, 7, 8, 9, 9, 9, 9, 9, 10, 9, 5, 7, 6, 6, 6, 6, 7, 6, 9, 9, 10, 9, 10, 9, 10, 10, 7, 6, 7, 7, 7, 7, 9, 7, 5, 7, 6, 6, 7, 6, 7, 7, 5, 6, 2, 3, 6, 6, 4, 3, 6, 6, 7, 6, 7, 7, 9, 7, 6, 6, 4, 3, 7, 7, 7, 6, 5, 7, 7, 6, 6, 6, 7, 7, 5, 6, 6, 6, 2, 3, 4, 3, 6, 6, 7, 7, 7, 6, 9, 7, 6, 6, 7, 7, 4, 3, 7, 6, 5, 6, 6, 6, 6, 6, 7, 7, 8, 9, 5, 6, 5, 6, 2, 5, 2, 3, 4, 3, 4, 3, 7, 6, 5, 6, 2, 5, 2, 5, 4, 1}; int main () { int cas; char p[10]; scanf("%d", &cas); while (cas--) { scanf("%s", p); int ret = 0; for (int i = 0; i < 8; i++) ret = ret * 2 + p[i] - '0'; printf("%d\n", ans[ret]); } return 0; }