Write a function that takes an unsigned integer and returns the number of ’1’ bits it has (also known as the Hamming weight).
For example, the 32-bit integer ’11’ has binary representation 00000000000000000000000000001011, so the function should return 3.
解题思路1
每一位分别和1进行与运算,统计结果不为0的位数。
实现代码1
//Runtime:10 ms
#include
#include "inttypes.h" using namespace std; class Solution { public: int hammingWeight(uint32_t n) { int i = 0; while (n) { i += n & 0x1; n >>= 1; } return i; } }; int main() { Solution s; cout<
解题思路2
每次n&(n-1)可以将n里面的值为1的位数减少一位
实现代码2
//Runtime:11 ms
class Solution {
public:
int hammingWeight(uint32_t n) {
int i = 0;
while (n)
{
n &= (n-1);
++i;
}
return i;
}
};