Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order.
For example,
Given n = 3,
You should return the following matrix:
[
[ 1, 2, 3 ],
[ 8, 9, 4 ],
[ 7, 6, 5 ]
]
public class Solution {
int[][] res;
int seq = 1;
public int[][] generateMatrix(int n) {
res = new int[n][n];
help(n, 0);
return res;
}
private void help(int n, int step) {
if (step > n / 2)
return;
if (step == n / 2 && n % 2 != 0) {
res[n / 2][n / 2] = seq++;
return;
}
for (int i = step; i < n - step - 1; i++)res[step][i] = seq++;
for (int i = step; i < n - step - 1; i++)res[i][n - step - 1] = seq++;
for (int i = n - step - 1; i > step; i--)res[n - step - 1][i] = seq++;
for (int i = n - step - 1; i > step; i--)res[i][step] = seq++;
help(n, ++step);
}
}